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3 years ago

What is -2 1/4 plus -3/4

Mathematics

2 answers:

Yuliya22 [10]3 years ago

7 0

Answer:

-3

Step-by-step explanation:

MissTica3 years ago

7 0

Answer:

24/8

Step-by-step explanation:

it so easy just add it altogether

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A coordinate plane with a line passing through (0, negative 3), (2, 0), and (4, 3).

Allushta [10]

Answer:

y= (3/2)x-3

Step-by-step explanation:

We need two points to find the equation of a line. Let's take (2,0) and (4, 3).

In the equation y=mx+b, m represents the slope. To find the slope, we can calculate the change in y/change in x. For (2,0) and (4,3), the change in y is 3-0=3 and the change in x is 4-2=2. Therefore, our slope is 3/2.

Then, in the equation y=mx+b, we can plug 3/2 in for m to get y = (3/2)x+b. To find b, we can plug one point in, such as (2.0), to get 0=(3/2)(2) + b, 0=3+b, and b=-3, making our equation

y= (3/2)x-3

8 0

2 years ago

CAN ANYONE HELP ME ON THIS

SpyIntel [72]

Answer:

i can help

Step-by-step explanation:

what the question

7 0

2 years ago

I have a slope of -4 (m=-4), would that be negative four over positive one or would that be negative 4 over negative one?

katrin [286]

If you have a slope of -4 then it would be -4/1 because rise/run. If it were -4/-1 then the slope would be 4.

3 0

3 years ago

Write the equation of a parabola having the vertex (1, −2) and containing the point (3, 6) in vertex form. Then, rewrite the equ

In-s [12.5K]

PART A

The equation of the parabola in vertex form is given by the formula,

$y - k = a {(x - h)}^{2}$

where

$(h,k)=(1,-2)$

is the vertex of the parabola.

We substitute these values to obtain,

$y + 2 = a {(x - 1)}^{2}$

The point, (3,6) lies on the parabola.

It must therefore satisfy its equation.

$6 + 2 = a {(3 - 1)}^{2}$

$8= a {(2)}^{2}$

$8=4a$

$a = 2$
Hence the equation of the parabola in vertex form is

$y + 2 = 2 {(x - 1)}^{2}$

PART B

To obtain the equation of the parabola in standard form, we expand the vertex form of the equation.

$y + 2 = 2{(x - 1)}^{2}$

This implies that

$y + 2 = 2(x - 1)(x - 1)$

We expand to obtain,

$y + 2 = 2( {x}^{2} - 2x + 1)$

This will give us,

$y + 2 = 2 {x}^{2} - 4x + 2$

$y = {x}^{2} - 4x$

This equation is now in the form,

$y = a {x}^{2} + bx + c$
where

$a=1,b=-4,c=0$

This is the standard form

7 0

3 years ago

Write 0.00052 in scientific notation.

Kamila [148]

10 over the power of negative 4

4 0

2 years ago