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UNO [17]
3 years ago
12

What is the value of (−23) –[(−25) – {(−17) –(−19)}

Mathematics
1 answer:
o-na [289]3 years ago
5 0
The answer is four.
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Figure GHTA below is a parallelogram. = 6 cm, = 8 cm, and the measure of = 60°. Find the area.
Kruka [31]

Answer:

multiply

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Hello, can i please have help on this question thank you
cricket20 [7]

Answer:

Step-by-step explanation:

a) One can get maximum score when all the 20 questions answered are correct.

Maximum score = 20*3 = 60 points

b) Minimum score = 20 * (-2) = -40 points

c) Points for correctly answered questions = 10*3 = 30

Incorrectly answered questions = 14 - 10 = 4

Points for incorrectly answered questions = 4 * (-2) = -8

Total score = 30 + (-8) = 22

d) Points for correctly answered questions =5*3 =  15

Points for incorrectly answered questions = 13 * (-2) = -26

Total score = 15 + (-26) = -11

6 0
3 years ago
Triangle with base of 12 and height of 10. what is the other number?????????
victus00 [196]
120 is the other number. 
6 0
3 years ago
Which function could be represented by the graph on the coordinate plane?
spin [16.1K]

Answer:

\boxed{f(x)=(x-8)^2-6}

Step-by-step explanation:

The graph in the attachment is a quadratic function whose vertex is in the fourth quadrant.

The coordinates of a point in the fourth quadrant is of the form (x,-y)

Considering the options, the vertex must have coordinates (h,k)=(8,-6) and a=1.


The quadratic function in vertex form is written as;

f(x)=a(x-h)^2+k

Therefore the equation of the quadratic function is;

f(x)=(x-8)^2-6


The correct answer is option D


8 0
3 years ago
Determine the unknown angle measures in the figure.<br><br>HELP NOW!!! please
maw [93]

Answer:

m∠1=80°

m∠2=112°

m∠3=131°

m∠4=80°

m∠5=37°

Step-by-step explanation:

First you have to find m∠2

To do that find m∠6 (I created this angle shown in pic below)

Find m∠6 by using the sum of all ∠'s in a Δ theorem

m∠6=180°-(63°+49°)

m∠6=68°

Now you can find m∠2 with the supplementary ∠'s theorem

m∠2=180°-68°

m∠2=112°

Then you find m∠5 using the sum of all ∠'s in a Δ theorem

m∠5=180°-(112°+31°)

m∠5=37°

Now you can find m∠1

m∠1=180°-(63°+37°)

m∠1=180°-100°=80°

m∠4 can easily be found too now:

m∠4=180°-(63°+37°)

m∠4=80°

m∠3=180°-49°

m∠3=131°

8 0
3 years ago
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