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UNO [17]
3 years ago
12

What is the value of (−23) –[(−25) – {(−17) –(−19)}

Mathematics
1 answer:
o-na [289]3 years ago
5 0
The answer is four.
You might be interested in
Rewrite the product as a sum: 10cos(5x)sin(10x)
mote1985 [20]

Answer:

10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

Step-by-step explanation:

In this question, we are tasked with writing the product as a sum.

To do this, we shall be using the sum to product formula below;

cosαsinβ = 1/2[ sin(α + β) - sin(α - β)]

From the question, we can say α= 5x and β= 10x

Plugging these values into the equation, we have

10cos(5x)sin(10x) = (10) × 1/2[sin (5x + 10x) - sin(5x - 10x)]

= 5[sin (15x) - sin (-5x)]

We apply odd identity i.e sin(-x) = -sinx

Thus applying same to sin(-5x)

sin(-5x) = -sin(5x)

Thus;

5[sin (15x) - sin (-5x)] = 5[sin (15x) -(-sin(5x))]

= 5[sin (15x) + sin (5x)]

Hence,  10cos(5x)sin(10x) =  5[sin (15x) + sin (5x)]

8 0
3 years ago
PLS HELP ME ASAP FOR 12 (SHOW WORK!!)
alex41 [277]
160 is the first because 1 inches 20 but it says 2 inches so at 40+40+40+40
and the 2nd part is yes he is correct because he converted the inches into feet so i think he is also correct
6 0
3 years ago
Que How does your tessellation with triangles relate to hexagons and tessellating the plane? Type your response in the space bel
madreJ [45]

For a regular tessellation, the shapes can be duplicated infinitely to fill a plane such that there is no gap. The only shapes that can form regular tessellations are equilateral traingle(all sides are equal. This means that it can be turned to any side and it would remain the same), square and regular hexagon. Looking at the given options, we have

Shape Tessellate?

Octagon No

Hexagon Yes

Pentagon No

Square Yes

Triangle No(unless it is specified that it is an equilateral triangle)

5 0
1 year ago
What is (x - 4y) (-3x - 2y) = ?
Artemon [7]
The answer is -3x^2+10xy+8y^2
3 0
4 years ago
If you draw a card with a value of 4 or less from a standard deck of cards, I will pay you 165$ if not your pay me $45. (Aces ar
jekas [21]

Answer: The required expected value is $3.46.

Step-by-step explanation:

Since we have given that

Number of value of 4 or less are

2,3,4

So, there are 12 in numbers.

So, probability would be

\dfrac{12}{52}

Since Aces are considered as the highest card in the deck.

So, remaining probability would be

\dfrac{40}{12}

Amount paid or value of 4 or less = $165

Amount not paid for other case = $45

So, the expected value would be

\dfrac{12}{52}\times 165-\dfrac{40}{52}\times 45\\\\=\dfrac{1980}{52}-\dfrac{1800}{52}\\\\=\dfrac{180}{52}\\\\=3.46

Hence, the required expected value is $3.46.

7 0
3 years ago
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