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4 years ago

If the rule for the sequence is 4n-1,what is the 3rd term?

Mathematics

1 answer:

kirill [66]4 years ago

6 0

$a_{3}$ = 11

to find the third term, substitute n = 3 into the rule

$a_{3}$ = (4 × 3 ) - 1 = 12 - 1 = 11

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Write three different equivalent expressions to 5(2x + 6) +25x + 12.

elena-s [515]

5(2x+6)

2x+6+25

25x+12

6 0

3 years ago

P and a are on points on the line 4x+2y=8. What are the coordinates?

KATRIN_1 [288]

(0, 4) and (2, 0) are the coordinates

8 0

3 years ago

Read 2 more answers

The center of a circle lies on _____.

algol [13]

<h2>Answer:</h2>

A) every diameter

<em>The center of a circle lies on </em><em>every diameter.</em>

<h2>Explanation:</h2>

B) The circle: A circle is a two-dimensional shape where all points are the same distance from the center. So this definition doesn't match the definition of the center of the circle. The center is just a point not several ones.

C) A tangent line: obviously this definition is false. A tangent line is a line not a point.

D) Every chord: A chord is any line segment between two points on a circle. The only chord that passes through is the diameter. So this definition does not include all the chords of a circle

A) Every diameter: This is the correct option! A diameter is any chord that <em>passes through the center</em>.

4 0

4 years ago

MAKE SURE TO SHOW WORK<br> solve for c:<br> a=7b+8c+9d-10

Slav-nsk [51]

<span>a=7b+8c+9d-10
8c = a - 7b - 9d + 10
c = (</span>a - 7b - 9d + 10) / 8

5 0

3 years ago

I need help on nine and 10 instructions say to solve these equations by cross multiplying

Aneli [31]

Answer:

9. a = -1

10. b = 20

Step-by-step explanation:

The term "cross multiplying" is used to describe the appearance of the result of multiplying both sides of the equation by the product of the denominators. The result is the left numerator is multiplied by the right denominator, and the right numerator is multiplied by the left denominator. The property of equality that supports this is the multiplication property of equality, which tells you the values of the variables are unchanged if you multiply both sides by the same thing. That multiplier is chosen so that it cancels the denominators.

$\dfrac{2a-5}{3a-4}=\dfrac{2a-3}{3a-2}\\\\(3a-2)(2a-5)=(3a-4)(2a-3)\qquad\text{"cross multiply"}\\\\6a^2 -19a +10=6a^2-17a+12\qquad\text{expand}\\\\-2=2a\qquad\text{add $19a-6a^2-12$}\\\\\boxed{a=-1}\qquad\text{divide by 2}$

$\dfrac{b-2}{b-6}=\dfrac{b+2}{b-4}\\\\(b-4)(b-2)=(b-6)(b+2)\qquad\text{"cross multiply"}\\\\b^2-6b+8=b^2-4b-12\qquad\text{expand}\\\\20=2b\qquad\text{add $6b+12-b^2$}\\\\\boxed{b=20}\qquad\text{divide by 2}$

_____

<em>Additional comments</em>

Here are the answer checks:

9. (2(-1) -5)/(3(-1)-4) = (2(-1)-3)/(3(-1)-2) ⇒ -7/-7 = -5/-5 . . . yes

10. (10 -2)/(10 -6) = (10 +2)/(10 -4) ⇒ 8/4 = 12/6 . . . yes

Sometimes this method of solving the problem will result in extraneous solutions. Those will generally be values of the variable that make one or more of the denominators be zero. You must be careful to exclude those values from any possible solution set.

5 0

3 years ago