Andrew gets paid $12.05 cents per hour
Answer:
Your selection is appropriate
Step-by-step explanation:
A negative exponent in the numerator is equivalent to a positive exponent in the denominator, and vice versa.
... a⁻² = 1/a²
____
2⁴ multiplies the variable expression no matter which way it is written.
The value of p = 11
y = 5x + p
1 = 5(-2) + p
1 = -10 + p
11 = p
The formula for area is pi x r^2 (pi times radius squared) so, for number 7 youre given the radius or "r", which is half the length of the inside of the cirlce. On a calculator: you would do 8 times 8 (8^2) because that's the radius squared and then you should get 64 and times 64 by 3.14 or use the pi button depending on what your teacher prefers you to use.
When you're given diameter or "d" which represents the is equal to the radius times 2. So, for example, number 8 the diameter is 26 so, the radius is 13. Use the formula for area just like in number 7 to find the area of this circle.
Make sure you pay attention to what information youre given (whether its "d", Diameter, "r" or radius. Use those two lists of steps for solving numbers 7 through 12.
For numbers 13-15: use the number (22/7) instead of 3.14 or the pi button on your calculator and do the same steps!!!!!
Let me know if you still need help after this:) happy math solving!
Answer:
the lower right matrix is the third correct choice
Step-by-step explanation:
Your problem statement shows that you have correctly selected the matrices representing the initial problem setup (middle left) and the problem solution (middle right).
Of the remaining matrices, the upper left is an incorrect setup, and the lower left is an incorrect solution matrix.
__
We notice that in the remaining matrices on the right that the (2,3) term is 0, and the (3,2) and (3,3) terms are both 1.
The easiest way to get a 0 in the 3rd column of row 2 is to add the first row to the second. When you do that, you get ...
![\left[\begin{array}{ccc|c}1&1&1&29000\\1+2&1-3&1-1&1000(29+1)\\0&0.15&0.15&2100\end{array}\right] =\left[\begin{array}{ccc|c}1&1&1&29000\\3&-2&0&30000\\0&0.15&0.15&2100\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C1%2B2%261-3%261-1%261000%2829%2B1%29%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Cc%7D1%261%261%2629000%5C%5C3%26-2%260%2630000%5C%5C0%260.15%260.15%262100%5Cend%7Barray%7D%5Cright%5D)
Already, we see that the second row matches that in the lower right matrix.
The easiest way to get 1's in the last row is to divide that row by 0.15. When we do that, the (3,4) entry becomes 2100/0.15 = 14000, matching exactly the lower right matrix.
The correct choices here are the two you have selected, and <em>the lower right matrix</em>.
