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Tju [1.3M]
2 years ago
15

Suppose account numbers for an internet service provider consist of alpha-numeric characters. The first character is a digit (0

through 9). The next 2 characters are capital letters (A through Z) and the last four characters are digits. How many account numbers are possible if no digit appears more than once? Your Answer:
Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
6 0

Answer:

20,442,240 account numbers are possible.

Step-by-step explanation:

The first character has 10 possible values.

The next 2 has 26 * 26 = 676 possible combinations.

The last 4 has 9*8*7*6 = 3024 possible combinations.

So the answer is 10 * 676 * 3024

= 20,442,240.

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Round you answer to the nearest cent
Zolol [24]

Answer:

$2.00

Step-by-step explanation:

3 0
3 years ago
Because of high production-changeover time and costs, a director of manufacturing must convince management that a proposed manuf
7nadin3 [17]

Answer:

See explanation below

Step-by-step explanation:

Here, a director of manufacturing must convince management that a proposed manufacturing method reduces costs before the new method can be implemented. The current production method operates with a mean cost of $220 per hour.

a) The alternative and null hypotheses would be:

H0: μ ≥ 220

Ha: μ < 220

b) Comment on the conclusion when H0 cannot be rejected:

When we fail to reject the null hypothesis H0, there is not enough evidence to conclude that the mean cost can be reduced from $220. Therefore the manager's proposed method cannot be implemented.

c) Comment on the conclusion when H0 can be rejected:

When the null hypothesis, H0 is rejected, there is enough evidence to conclude that the mean cost can be reduced from from $220. Therefore the manager's proposed method can be implemented.

3 0
3 years ago
The graph of function f is shown. Function g is represented by the table. Which statement correctly compares the two functions?
Dafna1 [17]

Answer:

Option (A)

Step-by-step explanation:

Graph of function 'f' represents,

x - intercept of the function 'f' → (1, 0)

y - intercept of the function → (0, 6)

As x-approaches ∞, value of the function approaches (-2)

Points in the given table is for the another function 'g'

x - intercept of the function 'g' → (1, 0) [For x - intercept, y = 0]

y - intercept of the function 'g' → (0, 3) [For y - intercept, x = 0]

As x approaches ∞, value of function 'g' approaches (-1).

Therefore, x - intercepts of both the functions are same but end behavior are different when x → ∞.

Option (A) will be the answer.

7 0
3 years ago
A farmer wants to use 200 feet of fencing for a chicken pen. He wants the width of the pen to be 20 feet. What is the length of
Aneli [31]
The length should be 80 feet.

This is because the width is 20, since there are two sides for the width in a pen, we have to add 20+20. This would equal 40. Then we need to subtract 40 from 200. 200-40 would be 160. Then since there are two sides for the length, we need to split that in half. 160÷2 would be 80. To double check, you can do 80+80 and that would still be 160. So the length of one side would be 80. But of course, this whole thing would only be right if the pen has four sides(but since i have seen many chicken pens, there were all rectangular). I hope this helped! :)
7 0
3 years ago
. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu
jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0
3 years ago
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