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Tju [1.3M]
2 years ago
15

Suppose account numbers for an internet service provider consist of alpha-numeric characters. The first character is a digit (0

through 9). The next 2 characters are capital letters (A through Z) and the last four characters are digits. How many account numbers are possible if no digit appears more than once? Your Answer:
Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
6 0

Answer:

20,442,240 account numbers are possible.

Step-by-step explanation:

The first character has 10 possible values.

The next 2 has 26 * 26 = 676 possible combinations.

The last 4 has 9*8*7*6 = 3024 possible combinations.

So the answer is 10 * 676 * 3024

= 20,442,240.

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zavuch27 [327]

Answer:

5

Step-by-step explanation:

Okay, so adding negative numbers can get very tricky, but I think I can help

Since there are two negative signs next to each other, they both cancel out and become positive so instead you get

-2+7

And if you do this with a number line, if you start and negative 2 and keep going right 7 times, you get 5

I hope I helped! I know negative numbers can be really difficult, but once you get the hang of it I bet you'll be great!

8 0
3 years ago
What is an equation of the line that passes through the points (8, -3) and (8,4)
weeeeeb [17]

Answer:

x = 8

Step-by-step explanation:

Notice that the x-coordinates of the two points are both 8.  Thus, the points are on the vertical line x = 8.

3 0
3 years ago
Which multiplication equation represents the question: how many 3/8s are in 5/4?
Harman [31]

Answer:

The equation which represents the question is 3 1/3

8 0
2 years ago
What is the measure of angle A in the triangle?<br> Enter your answer in the box.<br> mZA=
stepladder [879]

Answer:

50

Step-by-step explanation:

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A + B + C = 180

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Combine like terms

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Subtract 90 from each side

3x+90-90=180-90

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Divide by 3

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A = 2x-10

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6 0
3 years ago
Read 2 more answers
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pentagon [3]

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3 0
3 years ago
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