The GCF of 15 and 25 would be 5
Answer:
a^3-125
Step-by-step explanation:
(a-5)(a^2+5a+25)
a^3+5a^2+25a-5a^2-25a-125
a^3+5a^2-5a^2+25a-25a-125
a^3-125
Given:
μ = 89 ng/ml, population mean
σ = 23 ng/ml, population standard deviation
Random variable, x = 100
To test P(x < 100), calculate the z-score.
z = (x-μ)/σ = (100 - 89)/23 = 0.4783
From standard tables, obtain
P(x < 100) = 0.6838 = 68.4%
Answer: 68.4%
