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Vinil7 [7]
3 years ago
7

Lexi needs 144 beads. A large box holds 100 beads. A medium box holds 10 beads. A small box holds 1 bead. Lexi already had 1 lar

ge box and 4 small boxes. How many medium boxes of beads she needs?
Mathematics
1 answer:
Masja [62]3 years ago
3 0
Lexi needs four medium boxes
You might be interested in
Need help asap pleas and thank you .
Arisa [49]

Answer:

The answer that is <em>not </em>true when x = -4 is <u>B</u>.

Step-by-step explanation:

Since x = -4, that means all we have to do to eliminate answers is plug -4 in place of x.

A is incorrect because 2 × -4 = -8, which means that answer IS true and we're looking for the one that isn't true.

Same with C, -4 + -4 + -4 added together gives you -12 = -12, therefore isn't the right choice.

Finally D. -4/4 divided equals -1, so that would make it -1 = -1.

B is the only one that doesn't make sense, therefore you have your answer.

4 0
3 years ago
Solve the system <br> 5x+3y=-9 &amp;- 2x+y=8
lianna [129]
5x+3y=-9
-2x+y=8

The first step is the trickery (and quite frankly, hardest to explain) part. You need to multiply one equation by a number that will create one variable to be the negative version of the other...(Confusing, right? Don't worry, I'll show you)

We are going to solve for X first.

We will multiply the second equation by -3
5x+3y=-9
-3(-2x+y)=(-3)8

Now simplify:
5x+3y= -9
6x-3y= -24

Now combine the two equations (add them together)
11x= -33
Divide by 11
X=-3

Now plug X in to one of the first equations:
5(-3)+3y= -9
-15+3y =-9
3Y= 6
Y= 2


So your final answer is:
x= -3
Y= 2

Hope this helps!
3 0
3 years ago
Read 2 more answers
3x-5y=-6<br> -9x-5y=18<br> whats the answer
Firlakuza [10]
\left \{ {{3x-5y=-6\ \ | *3} \atop {-9x-5y=18}} \right. \\\\  \left \{ {{9x-15y=-18} \atop {-9x-5y=18}} \right. \\+----\\add\ both\ equations\\\\&#10;-20y=0\ \ \ | divide\ by \ -20\\\\&#10;y=0\\\\&#10;3x-5y=-6\ \ \ \ add\ 5y\\\\&#10;3x=-6+5y\ \ \ | divide\ by\ 3\\\\&#10;x=\frac{-6+5y}{3}=\frac{-6+0}{3}=-2\\\\ x=-2\\ y=0
4 0
2 years ago
Read 2 more answers
What’s the least common multiple of x^2-2x-15 and x^2+2x-3?
Ghella [55]

Answer:

\large\boxed{LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)}\\\boxed{=x^3-3x^2-13x+15}

Step-by-step explanation:

x^2-2x-15=x^2+3x-5x-15=x(x+3)-5(x+3)=(x+3)(x-5)\\\\\\x^2+2x-3=x^2+3x-1x-3=x(x+3)-1(x+3)=(x+3)(x-1)\\\\LCM(x^2-2x-15,\ x^2+2x-3)=(x+3)(x-5)(x-1)\\\\=(x^2-2x-15)(x-1)\qquad\text{use FOIL}\\\\=(x^2)(x)+(x^2)(-1)+(-2x)(x)+(-2x)(-1)+(-15)(x)+(-15)(-1)\\\\=x^3-x^2-2x^2+2x-15x+15\qquad\text{combine like terms}\\\\=x^3+(-x^2-2x^2)+(2x-15x)+15\\\\=x^3-3x^2-13x+15

4 0
3 years ago
Write the given numbers in order from what smallest to largest of 6, -9, -12, 8
sasho [114]
-12, -9, 6, 8 because negatives are smaller than positives.
5 0
3 years ago
Read 2 more answers
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