All categories

2 years ago

The Eiffel Tower is 324 m tall. If a tourist is looking at it from 100 m away from the base,

Mathematics

1 answer:

romanna [79]2 years ago

4 0

Answer:

80,94º

Step-by-step explanation:

What I've done is, first draw a triangle with a 90º angle and write down the height (324m) and the tourist's distance (100m).

So I calculated the tangent of the angle of the tourist.

The formula is tan=Oposite side/adjacent

$tan=\frac{opposite side}{adjacent}$

$tan=\frac{324}{100} =3.24$

And now with your calculator you press "shift" and "tan". Then introduce 3,24 and it will give you the result (80,94º).

I hope it helped.

You might be interested in

The Candy Shack sells 138 pounds of candy on Tuesday. They sold 71.76 pounds of jelly beans. What percent of the candy sold was

Pepsi [2]

Answer:

<h2>52% were jelly beans!</h2>

Explanation:

Cross multiply the following:

$\frac{x}{100} = \frac{71.76}{138}$

x times 138 = 138x

100 times 71.76 = 7,176

Divide both sides by 138:

$\frac{138x}{138} = \frac{7176}{138}$

6 0

3 years ago

Read 2 more answers

Please help and show work!!

Paladinen [302]

B. Because 20 is greter than 18.

6 0

3 years ago

Read 2 more answers

A submarine sits at -300 meters in relation to sea level. Then it descends 115 meters. What is it’s new position in relation to

Anna71 [15]

Answer:

A. -415m

Step-by-step explanation:

-300 meters is the starting point.

Then, the submarine goes 115m further below the surface, which can be represented as -115.

Add -300 and -115 and you get -415m.

3 0

3 years ago

G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d

____ [38]

By definition of covariance,

$\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]$

$\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]$

We have

$\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]$

$=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

$\mathbb E[aX-b]=a\mathbb E[X]-b$

$\mathbb E[cY-d]=c\mathbb E[Y]-d$

$\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd$

Putting everything together, we find the covariance reduces to

$\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)$

as desired.

5 0

2 years ago

If the original price of $100 is decreased by 10% and subsequently

denpristay [2]

Answer:

Step-by-step explanation:

6 0

3 years ago