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bezimeni [28]
3 years ago
10

Jim rented a truck for one day. There was a base fee of $17.99, and there was an additional charge of 76 cents for each mile dri

ven. Jim had to pay $236.11 when he returned the truck. For how many miles did he drive the truck?
Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:

287 miles

Step-by-step explanation:

The base fee was $17.99 and an additional 76 cents ($0.76) for every mile.

We can represent the amount he will pay for rent with the equation below:

C = 17.99 + 0.76m

where m = number of miles driven

Jim paid $236.11, therefore:

236.11 = 17.99 + 0.76m

0.76m = 236.11 - 17.99

0.76m =218.12

m = 218.12 / 0.76 = 287 miles

Jim drove 287 miles.

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You just find out what the missing variable is by subtracting 88 from 107 on the first one. You do the same for the last too as-well, but just insert the numbers that they say.

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3 0
3 years ago
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I need help with this problem
Soloha48 [4]

Answer:

3.\ \dfrac{3x}{11x}, \dfrac{6}{22},  \dfrac{9}{33},\dfrac{12}{44}

4. -18\\5.\ 400

Step-by-step explanation:

<u>Solution 3:</u>

Equivalent fractions to are to \frac{3}{11} be found out.

<u>Method: </u> By Multiplying both the denominator and numerator with the same number, we can easily find equivalent fractions.

1. Multiply with 2:

\dfrac{3 \times 2}{11 \times 2}\\\Rightarrow \dfrac{6}{22}

2. Multiply with 3:

\dfrac{3 \times 3}{11 \times 3}\\\Rightarrow \dfrac{9}{33}

3. Multiply with 4:

\dfrac{3 \times 4}{11 \times 4}\\\Rightarrow \dfrac{12}{44}

If we try to write in variable form, it can be written as:

\dfrac{3x}{11x}

where x is any number.

---------------

<u>Solution 4:</u>

(2x-10) when x=-4

2 \times (-4) -10\\\Rightarrow -8 -10\\\Rightarrow -18

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<u>Solution 5:</u>

(10a)^2, a=-2\\\Rightarrow \{10 \times (-2)\}^2\\\Rightarrow (-20)^2\\\Rightarrow 400

4 0
3 years ago
Graph a line that contains the point (3,-6) and has a slope of -1/2
djyliett [7]
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4 0
3 years ago
What happens to the value?
Fiesta28 [93]

Answer:

D.) c is multiplied by 4

Step-by-step explanation:

c = \dfrac{8a^3}{b}

If a is doubled, it becomes 2a. If b is doubled, it becomes 2b. Now we replace a with 2a and b with 2b and simplify.

c = \dfrac{8(2a)^3}{2b}

c = \dfrac{8 \times 8a^3}{2b}

c = \dfrac{4 \times 8a^3}{b}

c = 4 \times \dfrac{8a^3}{b}

Answer: D.) c is multiplied by 4

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2 years ago
The gross domestic product (GDP) of a certain country, which measures the overall size of the economy in billions of dollars, ca
DiKsa [7]

Answer:

The estimated GDP in 2007 is 12782 billion dollars.

The estimated GDP in 2011 is 15010 billion dollars.

The estimated GDP in 2012 is 15567 billion dollars.

Step-by-step explanation:

Consider the provided function.

g(y) = 557y +8883

Where y = 10 corresponds to the year 2010.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2007.

If y = 10 corresponds to the year 2010 then y = 7 corresponds to the year 2007.

Substitute the value of y = 7 in the provided function.

g(y) = 557(7) +8883

g(y) = 3899+8883

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Hence, the estimated GDP in 2007 is 12782 billion dollars.

Part (b) Estimate the GDP (to the nearest billion dollars) in 2011.

If y = 10 corresponds to the year 2010 then y = 11 corresponds to the year 2011.

Substitute the value of y = 11 in the provided function.

g(y) = 557(11) +8883

g(y) = 6127+8883

g(y) = 15010

Hence, the estimated GDP in 2011 is 15010 billion dollars.

Part (C) Estimate the GDP (to the nearest billion dollars) in 2012.

If y = 10 corresponds to the year 2010 then y = 12 corresponds to the year 2012.

Substitute the value of y = 12 in the provided function.

g(y) = 557(12) +8883

g(y) = 6684+8883

g(y) = 15567

Hence, the estimated GDP in 2012 is 15567 billion dollars.

4 0
3 years ago
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