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Rudiy27
3 years ago
12

Wolfgang wants to enlarge a picture he developed. Which factor listed below would scale up (enlarge) his picture the most if he

used it to multiply its current dimensions? 7/8 14/14 1 4/9 3/2
Mathematics
1 answer:
kirza4 [7]3 years ago
4 0
You want the largest number here. Both 14/9 and 3/2 are greater than one, so the other options can be eliminated. You can either convert to decimals, or put them over a common denominator.
For decimals, divide 14 by 9 to get 1.556. Then divide 3 by 2 to get 1.5.
If you want to stay in fractions, put them over a common denominator (18 in this case). 14*2->28/18. 3*9->27/18. In both cases, 14/9 is greater so you know your math is correct. 14/9 is the answer.
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Julia has 14 butterfly stickers. Daria has 26 butterfly stickers. How many more butterfly stickers does Daria have than Julia?
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Answer:

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Step-by-step explanation:

The word "more" in this context means we want to find the difference between the number Daria has and the number Julia has. It is an "additive" comparison.

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You need to be a little careful with this. You will often see wording such as "... <em>times more</em> than ...", in which case it is a multiplicative comparison. (I would prefer the multiplicative comparison wording to be "... times as many as ...", so that "more" is reserved for additive comparisons. Alas, not in this lifetime.)

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The circumference of a circle is 12pi feet. What is the diameter?
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35

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5 0
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Find the value of x in the figure
antoniya [11.8K]

Answer:

x = 100

Step-by-step explanation:

I know that the total is 180 so with that in mind this is what i did to get the answer.

180 - 57 = 123

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2 years ago
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Simplify 4√16 + 8√16
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4\sqrt{16} + 8\sqrt{16}:

Since \sqrt{1} =1, we get:

4\cdot \:1\cdot \:6+8\cdot \:1\cdot \:6=24+48=72

-----------------------------------------------------------------------------------

7\sqrt{4} *3\sqrt{8}

We have \sqrt{4}=2

simplify \sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}

then the radical rule is used: \quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

⇒ \sqrt{2^2*2} = \sqrt{2^2} \sqrt{2}= \sqrt{4}\sqrt{2} =2\sqrt{2}

Now we have \sqrt{4}=2 and \sqrt{8}=2 \sqrt{2}

7\sqrt{4} *3\sqrt{8} = 7*2*3*2\sqrt{2} = 84 \sqrt{2}

-----------------------------------------------------------------------------------

2\sqrt{4}+5 \sqrt{9}

2\sqrt{4} =2*2= 4 and 5\sqrt{9} =5*3= 15

2\sqrt{4}+5 \sqrt{9} = 4+15 = 19

-----------------------------------------------------------------------------------

4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}

since 2\sqrt{5} is the half of 4\sqrt{5}

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-4\sqrt{2}\:+\:5\sqrt{2} =1 \sqrt{2} = \sqrt{2}\\    <em>(-4+5=1)</em>

4 0
2 years ago
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