A
Step-by-step explanation:First, subtract
2
π
r
2
from each side of the equation to isolate the
h
term:
S
−
2
π
r
2
=
2
π
r
h
+
2
π
r
2
−
2
π
r
2
S
−
2
π
r
2
=
2
π
r
h
+
0
S
−
2
π
r
2
=
2
π
r
h
Now, divide each side of the equation by
2
π
r
to solve for
h
:
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
2
π
r
h
2
π
r
S
−
2
π
r
2
2
π
r
=
h
h
=
S
−
2
π
r
2
2
π
r
Or
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
2
π
r
2
2
π
r
h
=
S
2
π
r
−
r
2
r
h
=
S
2
π
r
−
r
Answer:
y = 3f(-1/5x + 1/5)
The function is
- vertical stretched by a factor of 3
- reflected across y-axis
- horizontal stretched by a factor of 5
- horizontal translated to the left 1/5 units
Step-by-step explanation:
Starting with: y = f(x)
Replacing x with -1/5x: y = f(-1/5x)
Replacing x with x - 1: y = f(-1/5(x - 1)) = f(-1/5x + 1/5)
Replacing y with 1/3y: 1/3y = f(-1/5x + 1/5) or y = 3f(-1/5x + 1/5)
The transformation:
- kf(x) vertically stretches the function by a factor of k (here k is 3)
- f(-x) reflects the function across y-axis
- f(bx) horizontally stretches the function by a factor of 1/b (here b is 1/5)
- f(x + c) horizontally translates the function left c units (here c is 1/5 units)
I think it is b but not for sure
Answer:
12.56 mm²
Step-by-step explanation:
Plug the given values into the area equation
Therefore, the area of the circle is 12.56 mm².
I hope this helps!