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loris [4]
2 years ago
14

Find a formula for the nth term in this arithmetic sequence:

Mathematics
1 answer:
Sati [7]2 years ago
8 0

The nth term of the arithmetic sequence is Tn = -7 + ( n - 1) 6

<h3>What is an arithmetic sequence?</h3>

An arithmetic sequence is defined as a sequence of numbers where the differences between every two consecutive terms is the same  through out the sequence.

The nth term of an arithmetic sequence is expressed as;

an = a + ( n - 1) d

Where;

  • a is the first term
  • n is the number of terms
  • d is the common difference

Substitute the values

an = -7 + ( n - 1) 6

Thus, the nth term of the arithmetic sequence is Tn = -7 + ( n - 1) 6

Learn more about arithmetic sequence here:

brainly.com/question/6561461

#SPJ1

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Rays dad bought a vintage car for $23000. If it increases in value 3% a year, how much will it be worth in 7 years?
kirill115 [55]

Answer:

It should be $27830 if I'm reading this right.

Step-by-step explanation:

3% of $23000 is $690

$690 * 7 = $4830

$23000 + $4830 = $27830

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3 years ago
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I’m confused on this one
ziro4ka [17]

Compare the values they have given you with the diagram. a, b and c are all sides of the triangle they want you to find the perimeter of. Knowing this, all you have to do is add a, b and c. h is not important because you don't count the altitude of a triangle when you calculate perimeter.

12 + 10 + 12 = 34

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3 years ago
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Two number that have a sum of 45 twice the greater number is six more than 5 times the lesser number
qaws [65]
The numbers will be X and Y with X being the lesser
x+y=45
2y=5x+6
now use a subtraction method to solve
x+y=45
y=45-x

2 (45-x)=5x+6
90-2x=5x+6
-7×=-84
x=12

y=45-12
y=33
so, x=12 and y=33
3 0
3 years ago
F(x)=X+2<br>g(x) = - 3x + 10<br>​
Fittoniya [83]

3 * 10 is 30 because 10 you would just add a zero behind the three

6 0
3 years ago
In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t
Basile [38]

So, since averages are defined as:

\frac{\sum_{k=1}^{P} P_k}{P}=70

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

\frac{\sum_{k=1}^{N} N_k}{N}=70

We can take both of these equations and multiply them by N:

\sum_{k=1}^{P} P_k=70P

\sum_{k=1}^N N_k=92N

So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}

Simplified we would have P/N=3/8.

7 0
3 years ago
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