Question

Find the derrivative please​

Answer 1

Answer:

Step-by-step explanation:

For this problem, we will need to use the product rule:

$h(x) = f(x)g(x)$

$h'(x) = f'(x)g(x) + f(x)g'(x)$

In this problem, $f(x) = x^{3}$ and $g(x) = \sqrt{2x + 3}$

Finding the derivative of each gives us the following:

$f'(x) = 3x^{2}$

$g'(x) = \frac{1}{\sqrt{2x + 3}}$

Plugging these values into the product rule gives us the final derivative:

$y'(x) = 3x^{2}\sqrt{2x + 3} + \frac{x^{3}}{\sqrt{2x + 3}}$