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Y_Kistochka [10]
3 years ago
5

Find the next three terms in the sequence. 3, 9, 27, 81

Mathematics
2 answers:
ehidna [41]3 years ago
8 0

Answer:

234

Step-by-step explanation:

Aliun [14]3 years ago
4 0

Answer:

243

Step-by-step explanation:

3*3=9*3=27*3=81*3=243*3 etc

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The question in the image.
GREYUIT [131]

Answer:

500 boxes

Step-by-step explanation:

<em>hey there,</em>

<em />

< Since "p" stands for profits, change "p" to 0 (since the question says 0 profits).

Here is how your equation would look like:

0 = -n^2 + 300n + 100000

Pretend like "n" is "x" since that is the variable we are trying to find here.

Solve for "n". Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

"n" actually ends up equaling 500, -200.

Obviously, negative can't be the answer because you can't have a negative amount of boxes. So 500 boxes would be your answer. 200 CAN'T be your answer <em>either </em>because it is a negative!! >

<u>Hope this helped! Feel free to ask anything else.</u>

6 0
3 years ago
I'm going to have a test later and i need help (p.s it show random ads just letting you know)
Sophie [7]

Answer:C

Step-by-step explanation:

8 0
3 years ago
What is the answer ?<br> x/y+17 <br> If is x=12 <br> and y=1/2
zavuch27 [327]

Answer:

jhhdh.duuemmeyyeymruur*

8 0
3 years ago
Read 2 more answers
Jordan bought 9/16 of a pound of sunflower seeds and divided them evenly into 9 snack bags for his lunch. What is the weight of
nikitadnepr [17]
(9/16)*(1/9) = 1/16 . . . . . . 1st selection
5 0
2 years ago
Read 2 more answers
A company determined that the marginal​ cost, C' (x )of producing the xth unit of a product is given by C' (x )= x^3- 6x. Find t
Rashid [163]

Answer:

C(x) = \frac{x^4}{4}-3x^2+3,000

Step-by-step explanation:

The marginal cost function, C'(x), is the derivate of the cost function, C(x).

Therefore, we can obtain the cost function by finding the integral of the marginal cost function:

C(x) = \int\ {C'(x)} \, dx \\C(x) = \int\ {(x^3-6x)} \, dx \\C(x) = \frac{1}{4} x^4-3x^2+a

Where 'a' is a constant and represents fixed costs. If fixed costs are $3,000, the cost function is:

C(x) = \frac{x^4}{4}-3x^2+3,000

3 0
3 years ago
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