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V125BC [204]
1 year ago
14

Mitosis is a process of cell reproduction in which one cell divides into two identical cells. A bacterium called E. coli often c

auses serious food poisoning. It can reproduce itself in 15 min.
a) Starting with one bacterium, make a table with time in
1/4-h blocks and the corresponding number of E. coli
bacteria up to 2 h of bacteria growth.
b) About how long will it take before there are 10 000 bacteria?
Mathematics
1 answer:
serious [3.7K]1 year ago
6 0

Answer:

I'm just a kid

Step-by-step explanation:

plssss give me brainkest

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Make a inequality
liraira [26]
To finish in 5 weeks:
For 4 of those weeks, read 4 chapters per week. On one of the weeks read 3 chapters.

To finish in 4 weeks:
For 3 of those weeks, read 5 chapters per week. On one of the weeks read 4 chapters.

To finish in 3 weeks:
For 2 of those weeks, read 6 chapters per week. On one of the weeks read 7 chapters.

To finish in 2 weeks:
On one week read 10 chapters. On the other week read 9 chapters.

To finish in 7 days:
For 6 of those days, read 3 chapters. On one of the days, read 1 chapter.
7 0
3 years ago
What is the inequality shown in the graph
rodikova [14]

It must be ≤ instead of ≥.

y ≤ - 3·x + 4

3 0
3 years ago
I need help with this please :)
Marina CMI [18]

9514 1404 393

Answer:

  all are Not Equivalent

Step-by-step explanation:

The coefficient of t³ in the target expression is -3. In order for that to be the result of simplifying any of the given expressions, they must have ( )^(t^3) in the denominator. None do, so none of the offered choices is equivalent to the given expression.

_____

The expressions simplify like this:

  \dfrac{(2^3)^{t^3}}{2^{5t}}=2^{3t^3-5t}\\\\\dfrac{8^{t^3}}{32^t}=2^{3t^3-5t}\\\\8^{t^3}\cdot32^t=2^{3t^3+5t}

4 0
2 years ago
The polynomial x^2+3x-1 is a factor of x^4+3x^3-2x^2-3x+1 true or false?
pashok25 [27]

Answer:

Yes, it is true that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1.

Step-by-step explanation:

Let us try to factorize x^4+3x^3-2x^2-3x+1

x^4+3x^3-2x^2-3x+1\\\Rightarrow x^4-2x^2+1-3x+3x^3

Let us try to make a whole square of the given terms:

\Rightarrow (x^2)^2-2\times x^2 \times 1+1^2+3x^3-3x\\\Rightarrow (x^2-1)^2+3x^3-3x\\

--------------

Formula used above:

a^{2} -2 \times a \times b +b^{2}  = (a-b)^2

In the above equation, we had a = x, b = 1.

--------------

Further solving the above equation, taking 3x common out of 3x^3-3x

\Rightarrow (x^2-1)^2+3x(x^2-1)\\

Taking (x^{2} -1) common out of the above term:

\Rightarrow (x^2-1)((x^2-1)+3x)\\\Rightarrow (x^2-1)(x^2+3x-1)

So, the two factors are (x^2-1)\ and\ (x^2+3x-1).

\therefore The statement that x^2+3x-1  is a factor of x^4+3x^3-2x^2-3x+1 is <em>True.</em>

7 0
2 years ago
Me.perez drove a total of 40 miles in 5 days she drove the same number of miles each day.how many miles did me.perez drive each
ahrayia [7]

Answer:

She drove 8 miles each day.

Step-by-step explanation:

Given that she drove equal number of miles in 5 days. So in order to find the number of miles in each days, you have to divide it by 5,

5days = 40miles

1day = 40 \div 5

1day = 8miles

8 0
3 years ago
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