3 years ago

Find the area (in square feet) of a trapezoid with height h and bases b1 and b2.

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

6 0

I think it’s the third one.

satela [25.4K]3 years ago

6 0

Formula for area of trapezoid is (b1+b2) divided by 2 then multiplied by height. So b1 + b2 is 9 + 12 which is 21. Then divide 21 by 2 you get 10.5. then multiply that by height, 10.5 x 6. The area is 63 feet squared.

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Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3

11Alexandr11 [23.1K]

Going out on a limb here and guessing that the function is

$f(x)=8x^2\tan^{-1}(7x^3)$

Please correct me if this isn't the case.

Recall that

$\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}$

which converges for $|x|$ .

It follows that

$8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}$
$=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}$

6 0

3 years ago

Need help solving this problem

ANTONII [103]

Here is the solution for the eqns.