M∠A′B′C′ = m∠ABC would be the answer for this. if you could give me a pic, I could answer. I don't see Triangle ABC
An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
2-4x^2+32x-25y^2-250y+589=0
3-81x^2+512x-64y^2-324y-3836=0
Answer:
Wow everyone is being so noice today is today some kind of special occassion?
Answer:
x is less than or equal to negative 14.
Step-by-step explanation:
so for now we should pretend that the greater than or equal to is an equal sign, and simplify the problem to get x alone on a side
remove 5 from each side
-x/3=1/3-5
-x/3=14/3
multiply both sides by 3
-x=14
x=-14
so we can now replace the equal sign with the equal or greater to, so x is less than or equal to -14
