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sertanlavr [38]
3 years ago
12

Maggie purchased 8 pounds of ground beef for $18.00. Which of the following does NOT represent the same price per pound?

Mathematics
1 answer:
agasfer [191]3 years ago
7 0

Answer: 5 pounds of ground beef ( don't see second :-( )

Step-by-step explanation: I found the unit rate per pound ( 2.25 ) and then multiplied that by the other pounds to compare the two prices and I only found 5 pounds to be incorrect, but I'll keep digging, hope this helps!

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3. Using the distributive property, write an equivalent expression. *<br> (5 Points)<br> 8(3x - 5)
julia-pushkina [17]

Answer:

24x - 40

Step-by-step explanation:

8 x 3 = 24

8 x 5 = 40

24x - 40

5 0
3 years ago
Read 2 more answers
A pet store sold 2 kittens and 1 puppy over the weekend the kittens sold for $9 each and the puppy sold $8 how much money did th
34kurt

Answer:

The answer is $26

Step-by-step explanation:

The pet store sold 2 kittens for $9 each which makes that 9+9 which equals 18

Now they sold 1 puppy for $8  so to get the total all together you will add 18+8 which equals 26. Thus they earned $26

8 0
3 years ago
How many american dollars can be cxchanged by NRs100000​
balandron [24]

Answer:

877.1929824561 dollars

Step-by-step explanation:

100000÷114= 877.1929824561 dollars

hope it helps!

4 0
3 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
The MTC Theater holds 250 people, and last night’s performance sold out!  Students paid $3.00 per ticket, while adults paid $5.0
Lilit [14]

9514 1404 393

Answer:

  • s + a = 250
  • 3s + 5a = 1050

Step-by-step explanation:

Let s and a represent the numbers of student and adult tickets sold. The system of equations that can be written from the given information is ...

  s + a = 250 . . . . . . total of tickets sold

  3s +5a = 1050 . . . dollar value of tickets sold

_____

The solution is (s, a) = (100, 150). 100 student tickets and 150 adult tickets were sold.

3 0
3 years ago
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