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Naya [18.7K]
3 years ago
5

Triangle MNO is equilateral. Find x and y.

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0
Again, your getting lost in the numbers. just think simply. a triangle has 180° and equilateral means all angles are exactly the same. Because of this, you know that m,n&o all equal 60°.

now it gets a little more complex when you split that to the smaller triangle and each of those have 180° within them.

it's safe to say that N is splitting it's full 60° equally between the three within it. making each one of the points at N equal to 20°. so solve for the rest to get y°.

We know M= 60°, O= 60°, N= 60° (20°,20°,20°) so to complete the triangle on the left we have one more angle that must be 100°. to complete the triangle on the right we have one more angle that must be 100° and to complete the center triangle we only know of 20° but have two equal angles left. So 180°-20°=160°. 160°÷2angles= 80° per angle to complete the center triangle.

that gives us y°=80°.

the X's are adding the smaller triangles to make the bigger triangle. so take 2x+4x+2x and divide that from the big triangle 180°. 8x=180° means x°=22.5°
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Colby and Danielle clean pools for extra money over the summer. Colby's income is determined by f(x) = 3x + 12, where x is the n
Nina [5.8K]
H(x) = 3x + 12 + 5x + 10
h(x) = 8x + 22

in 4 hrs Colby can make: 3(4)+12 = 24$
in 4 hrs Dan can make: 5(4)+10 = 30$
together they make 22+30=52$ in 4hrs
if split equally that's 52/2=26$ a piece
yes, Colby doesn't make as much money so he will benefit from teaming up with Dan.
6 0
3 years ago
Please answer this question (10) GIVING BRAINLIEST!!
sweet [91]
<h3>Answer:  y = 5</h3>

==============================================================

Explanation:

For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.

This means AC = BD.

Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations

  • AP = PC
  • BP = DP

We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.

---------------

By the segment addition postulate, we know that

BP+DP = BD

(-2x+23)+(3y-6) = BD

BD = -2x+3y+17

Since the diagonals are equal, we also know that AC = -2x+3y+17

We are given that AC = 2x+4

Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17

---------------

The conclusion of each the last two sections was the following two equations

  • -2x+23 = 3y-6
  • 2x+4 = -2x+3y+17

We have two equations and two unknowns. We have enough info to be able to find x and y.

Let's isolate 3y in the first equation

-2x+23 = 3y-6

3y-6 = -2x+23

3y = -2x+23+6

3y = -2x+29

Then we can plug this into the second equation

2x+4 = -2x+3y+17

2x+4 = -2x+(3y)+17

2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29

Now solve for x

2x+4 = -2x+(-2x+29)+17

2x+4 = -2x-2x+29+17

2x+4 = -4x+46

2x+4x = 46-4

6x = 42

x = 42/6

x = 7

We then use this to find y

3y = -2x+29

3y = -2(7)+29

3y = -14+29

3y = 15

y = 15/3

y = 5

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