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3 years ago

A bag of marbles weighs 2.3 kg. Each marble weighs 1.25 grams. How many pennies are in the bag?

Mathematics

1 answer:

Paha777 [63]3 years ago

6 0

None it doesn’t say anything about pennies in the bag just marbles

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Divide x to the 5 eighths power divided by x to the 1 fourth power.

8_murik_8 [283]

$\frac{x^{5/8}}{x^{1/4}} = x^{5/8-1/4}= x^{5/8-2/8}= x^{3/8} or \sqrt[8]{x^3}$

8 0

3 years ago

John is selling tickets to an event. Attendees can either buy a general admission ticket, x,

Masteriza [31]

John sold 18 general admission tickets and 11 VIP tickets.

Step-by-step explanation:

Given,

Cost of each general admission = $50

Cost of each VIP ticket = $55

Total tickets sold = 29

Total revenue generated = $1505

Let,

x represent the number of general admission tickets sold

y represent the number of VIP tickets.

x+y=29 Eqn 1

50x+55y=1505 Eqn 2

Multiplying Eqn 1 by 50

$50(x+y=29)\\50x+50y=1450\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2

$(50x+55y)-(50x+50y)=1505-1450\\50x+55y-50x-50y=55\\5y=55$

Dividing both sides by 5

$\frac{5y}{5}=\frac{55}{5}\\y=11$

Putting y=11 in Eqn 1

$x+11=29\\x=19-11\\x=18$

John sold 18 general admission tickets and 11 VIP tickets.

Keywords: linear equation, elimination method

Learn more about elimination method at:

#LearnwithBrainly

5 0

3 years ago

PLZ HELP!!! Use limits to evaluate the integral.

Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

$\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]$

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

$r_i=\dfrac{2i}n$

where $1\le i\le n$ . Each interval has length $\Delta x_i=\frac{2-0}n=\frac2n$ .

At these sampling points, the function takes on values of

$f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}$

We approximate the integral with the Riemann sum:

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3$

Recall that

$\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4$

so that the sum reduces to

$\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}$

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

$\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}$

Just to check:

$\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28$

4 0

2 years ago

How many 3/4 foot pieces of string can be cut from a piece of string 4 1/2 feet long

Gnom [1K]

3/4 foot is 9 inches, and 4 1/2 feet is 54 inches, so, 54/9 makes exactly 6 pieces of string.

8 0

2 years ago

What are the solutions of the inequality? x/5 _>-2

nata0808 [166]

X is greater than -10

5 0

3 years ago