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Ugo [173]
3 years ago
10

MATHS QUESTION Any help for another maths questions I just don't get what to do thank you ❤

Mathematics
1 answer:
levacccp [35]3 years ago
4 0
Look at the picture.

a) 180° - 45° = 135°


b) Use trigonometric function

\tan(\angle DBA)=\dfrac{45}{30}\\\\\tan(\angle DBA)=1.5\\\\m\angle DBA\approx56^o

270° - 56° = 214°


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A=2(L+W) solve for W
balu736 [363]
First you divide L+W by 2 and you would get A/2=L+W then you would subtract L and get A/2 -L=W
7 0
3 years ago
A=2x+6xz <br> a=2x+6xz<br> for x
Dennis_Churaev [7]
So I guess we are solving for x here :)
So here is my work...
a=2x+6xz
Basically I think it would be
a=6xz+2x

WAIT WAIT NO I'M WRONG FORGIVE ME!

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5 0
3 years ago
Read 2 more answers
The table shows a pattern of exponents.<br><br> What is the pattern as the exponents decrease?
Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0
3 years ago
Read 2 more answers
Help me plssssssssssssssssssssssssssssss
Naddika [18.5K]

Answer: See explanation (btw, the answer is always in bold letters)

Step-by-step explanation:

1.) 1 gallon for $1.99

1/2 gallon for $0.98

1 gallon would be 0.98 × 2 = <em>1.96</em>

2 gallons for $3.98

1 gallon would be 3.98 ÷ 2 = 1.99

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s = 3

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4.) This is a rectangle; the area of a rectangle is l × b.

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l × b = a

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Divide both sides by 6.9

b = 4.1

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5.) False

5 0
3 years ago
HELP ME PLZ?!!!?!?!?!?!
miss Akunina [59]

It is.................x+y=5

7 0
3 years ago
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