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QveST [7]
2 years ago
11

What is the difference of the fractions? Use the number line and equivalent fractions to help find the answer.

Mathematics
1 answer:
ipn [44]2 years ago
7 0

The difference of the fraction is \mathbf{  -\dfrac{3}{4}} by using equivalent expressions.

<h3>What is a number line?</h3>

A number line is a diagrammatic representation of real numbers on the graduated line. It ranges from negative axis to positive axis with 0 being the center position.

A sketch showing the representation of the difference in the mixed fractions can be seen in the image attached below.

Using equivalent expressions to determine the difference between the mixed fractions, we have;

\mathbf{ = -2\frac{1}{2} - (-1\dfrac{3}{4}) }

\mathbf{ = -2\frac{1}{2} +1\dfrac{3}{4} }

\mathbf{ = -\dfrac{5}{2} +\dfrac{7}{4} }

\mathbf{ = -\dfrac{3}{4}}

Learn more about number line here:

brainly.com/question/25230781

#SPJ1

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H(x) = 3х – 4<br> What is h(6)?
xeze [42]

Answer:

14

Step-by-step explanation:

h(6) means what is the value of h(x) when x is 6.

The value given for h(x) is 3x-4.

So we need to evaluate the expression 3x-4 for x=6.

Replace x with 6: 3(6)-4

Now perform order of operations.

3(6)-4

18-4

14

8 0
3 years ago
What is the domain and range of the following? (1,5) (-2,4) (-3,0) (-6,2)
miskamm [114]

Domain: {1, -2, -3, -6}

Range: {5, 4, 0, 2}

im not 100% sure but Im pretty sure it’s that

5 0
3 years ago
Read 2 more answers
I NEED HELP ON THIS PROBLEM PLS
dedylja [7]

Answer:

only A

Step-by-step explanation:

A is correct because if a number is less than 7, the number under the square root will be negative, and that will yield an imaginary (or non-real number)

B is incorrect because even if you choose a number less than 7, the result will still yield a real number

C is incorrect due to the same logic as B

D is incorrect because you can take the cube root of a negative number without it being non-real.

4 0
3 years ago
URGENT PLEASE GET THIS QUICKLY PLEASE<br> If f(x)= 2x+7, find f(2)=
Vaselesa [24]

Answer:

21

Step-by-step explanation:

2(2) +7

14+7

21

3 0
3 years ago
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This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex
noname [10]

L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)

L_x=10+10\lambda x=0\implies1+\lambda x=0

L_y=10+10\lambda y=0\implies1+\lambda y=0

L_z=2+4\lambda z=0\implies1+2\lambda z=0

L_\lambda=5x^2+5y^2+2z^2-42=0

\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z

5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1

z^2=1\implies z=\pm1\implies x=y=\pm2

There are two critical points, at which we have

f\left(2,2,1\right)=42\text{ (a maximum value)}

f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}

3 0
4 years ago
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