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prohojiy [21]
3 years ago
7

PLEASE HELPPPPPPPPPPPP ME! THANK YOU!

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

x=0

x=10

x=24

Step-by-step explanation:

f(x) = -.05x^2 + x +6

The initial value is 6 ( Let x=0  and f(0) = 6)

f(x) = -.05( x^2 -20 x -120)

I plotted the equation and maximum is at x=10 and the zero is at x=25

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A probability experiment is conducted in which the sample space of the experiment is Sequals=StartSet 9 comma 10 comma 11 comma
White raven [17]

Answer:

From both approaches P(F or G)=0.667

Step-by-step explanation:

P(F or G)=?

F={9, 10, 11, 12, 13}​

G={13,14,15,16}

Finding P(F or G) by counting outcomes in F or G

F or G={9, 10, 11, 12, 13}or {13,14,15,16}

F or G={9, 10, 11, 12,13,14,15,16}

number of outcomes in F or G=n(F or G)=8

S={9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20}​

number of outcomes in S=n(S)=12

P(F or G)=n(F or G)/n(S)

P(F or G)=8/12

P(F or G)=0.667

Finding P(F or G) by addition rule

P(F or G)=P(F)+P(G)-P(F and G)

F={9, 10, 11, 12, 13}​

number of outcomes in F=n(F)=5

P(F)=n(F)/n(S)

P(F)=5/12

P(F)=0.417

G={13,14,15,16}

number of outcomes in G=n(G)=4

P(G)=n(G)/n(S)

P(G)=4/12

P(G)=0.333

F and G={9, 10, 11, 12, 13}and {13,14,15,16}

F and G={13}

number of outcomes in F and G=n(F and G)=1

P(F and G)=n(F and G)/n(S)

P(F and G)=1/12

P(F and G)=0.083

P(F or G)=P(F)+P(G)-P(F and G)

P(F or G)=0.417+0.333-0.083

P(F or G)=0.667

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You can read 52 pages per hour.
lidiya [134]

Answer:

the standard is that a person can read 40 to 50 pages in an hour on average.

Step-by-step explanation:

52x2 is  104, and you need 130 pages it, i say that you cant complete the homework under two hours

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2 years ago
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Of the 168 hours in a​ week, as a full time​ student, you should spend how many hours per week on school​ work?
bonufazy [111]
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The time to fly between New York City and Chicago is uniformly distributed with a minimum of 120 minutes and a maximum of 150 mi
lara [203]

Answer:

a) 33.33%)

b) 135 minutes

c) 8.66 min

d) 50%

Step-by-step explanation:

a) the probability for a uniform distribution is

P(b<X<a) = (a-b)/(c-d) , where c and d are the maximum and minimum values

therefore the probability that the flight is more than 140 minutes ( and less than 150 since it is the maximum value)

P(140<X<150) = (a-b)/(c-d) = (150-140)/(150-120) = 10/30 = 1/3 (33.33%)

b) the mean (expected value) for a uniform probability distribution is

E(X) = (c+d)/2 = (120+150)/2 = 135 minutes

c)  the standard deviation for a uniform probability distribution is

σ²(X)= (c-d)²/12 = (150-120)²/12 = 75 min²

σ = √75 min² = 8.66 min

b) following the same procedure as in a)

P(120<X<135) = (a-b)/(c-d) = (135-120)/(150-120) = 15/30 = 1/2 (50%)

4 0
3 years ago
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