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Sloan [31]
3 years ago
15

MR Husted has a wooden parallelogram which has a height of 4 centimeters and a base of 11 centimeters. ms Henningsen also has a

parallelogram which has a height of 7 centimeters and a base of .15 meters. what is the combined area of their parallelograms in kilometers
Mathematics
1 answer:
Sholpan [36]3 years ago
7 0
I think its 0.0004505 or 6.2e-5.
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Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage. Determine the weight of a 170 cm steel bar
Bumek [7]

The weight of a 170 cm steel bar will be 5 Kg

Step-by-step explanation:

Derek uses a 136 cm flat steel bar that weighs 4 kg to make rack in the garage.

1 kg = 1000 gm

So the weight of 1 cm steel bar will be  \frac{4 }{136} kg

Weight of 1 cm bar = \frac{4000}{136} gm

Let the weight of a 170 cm steel bar will be \frac{4000 }{136} × 170 gm

⇒4000 × 1.25 gm

⇒ 5000 gm

⇒5 kg

Hence, the weight of a 170 cm steel bar will be 5 Kg

4 0
3 years ago
Help me please,Thanks;)
Sindrei [870]
I think its the second choice

8 0
2 years ago
Beth has already jogged 3 miles. She plans to jog less than 12 miles. Which inequality can be used to find the number of miles (
nika2105 [10]

Answer: Bilmem

Step-by-step explanation:

5 0
2 years ago
3x + ky = 8
sattari [20]

Answer:

(a): <u>x</u><u> </u><u>is</u><u> </u><u>3</u><u> </u><u>and</u><u> </u><u>ky</u><u> </u><u>is</u><u> </u><u>-</u><u>1</u>

<u>(</u><u>b</u><u>)</u><u>:</u><u> </u><u>k</u><u> </u><u>is</u><u> </u><u>-</u><u>2</u>

Step-by-step explanation:

Let: 3x + ky = 8 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em>

x - 2 ky = 5 be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em>

<em> </em>Then multiply <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>a</em><em>)</em><em> </em>by 2:

→ 6x + 2ky = 16, let it be <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em>

Then <em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>c</em><em>)</em><em> </em><em>+</em><em> </em><em>e</em><em>q</em><em>u</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>(</em><em>b</em><em>)</em><em>:</em>

<em>{ \sf{(6  + 1)x + (2 - 2)ky = (16  +  5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}</em>

<em>T</em><em>h</em><em>e</em><em>n</em><em> </em><em>k</em><em>y</em><em> </em><em>:</em>

{ \sf{2ky = 3 - 5}} \\ { \sf{ky =  - 1}}

{ \bf{y =  \frac{1}{2} }} \\ { \sf{ky =  - 1}} \\ { \sf{k =  - 2}}

4 0
3 years ago
In a function if the vaule of a changes in response to the vaule of b then b is the
d1i1m1o1n [39]
<span>b is the independent variable ok</span>
5 0
3 years ago
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