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3 years ago

Simplify completely.

" \sqrt{68} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Keith_Richards [23]3 years ago

3 0

$\bf \sqrt{68}\qquad 
\begin{cases}
68=2\cdot 2\cdot 17\\
\qquad 2^2\cdot 17
\end{cases}\qquad \sqrt{2^2\cdot 17}\implies 2\sqrt{17}$

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Step-by-step explanation:

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3 years ago

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Answer:

$\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

Step-by-step explanation:

The given expression is

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We need to simplify the expression such that answer should contain only positive exponents with no fractional exponents in the denominator.

Using properties of exponents, we get

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We can not simplify further because on further simplification we get negative exponents in numerator or fractional exponents in the denominator.

Therefore, the required expression is $\dfrac{x^{\frac{2}{3}}y^{\frac{1}{4}}}{4y^{2}}$ .

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