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skelet666 [1.2K]
3 years ago
14

1. There are apples, bananas, and pears in a basket. The probability of randomly picking an apple is to

Mathematics
1 answer:
Tamiku [17]3 years ago
7 0
Help me I will help you
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Ryan is X years old. Two times his age plus fifteen equals thirty-seven minus two. ( 2X + 15=37 - 2) Write an equation showing h
Misha Larkins [42]

Answer:

1) 10

2) 16

Step-by-step explanation:

1) 2x+15=37-2

2x+15=35

2x=35-15

2x=20

2 2

x=10

2)10x-8=9x+8

10x-9x=8+8

x=16

Hope this helps ❤

3 0
3 years ago
What is the measure of each exterior angle of a regular triangle
Sophie [7]

Answer:Each pair of interior angle and the exterior angle

So the exterior angle = 360° - the interior angle.

5 0
3 years ago
Read 2 more answers
Why is there always more than one parallelogram with the same area and base​
BaLLatris [955]

Answer:

If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.

6 0
1 year ago
The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typo
muminat

Answer:

The required probability is 0.55404.

Step-by-step explanation:

Consider the provided information.

The number of typographical errors on a page of the first booklet is a Poisson random variable with mean 0.2. The number of typographical errors on a page of second booklet is a Poisson random variable with mean 0.3.

Average error for 7 pages booklet and 5 pages booklet series is:

λ = 0.2×7 + 0.3×5 = 2.9

According to Poisson distribution: {\displaystyle P(k{\text{ events in interval}})={\frac {\lambda ^{k}e^{-\lambda }}{k!}}}

Where \lambda is average number of events.

The probability of more than 2 typographical errors in the two booklets in total is:

P(k > 2)= 1 - {P(k = 0) + P(k = 1) + P(k = 2)}

Substitute the respective values in the above formula.

P(k > 2)= 1 - ({\frac {2.9 ^{0}e^{-2.9}}{0!}} + \frac {2.9 ^{1}e^{-2.9}}{1!}} + \frac {2.9 ^{2}e^{-2.9}}{2!}})

P(k > 2)= 1 - (0.44596)

P(k > 2)=0.55404

Hence, the required probability is 0.55404.

4 0
3 years ago
What are the equivalent fractions for 2 1/5 and 1 5/6 using 30 as the common denominator
Anuta_ua [19.1K]

Answer:

2 6/30 and 1 25/30

Step-by-step explanation:

First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30

4 0
2 years ago
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