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4 years ago

Which number is a composite number 7 11 31 or 36 show your work.

2 answers:

6 0

Alrighty, so if I remember correctly a prime number is a number in which the number 1 and a number are the only factors of said number and a composite number has more than 1 and itself. 7: 7, 1 11: 11, 1 31: 31, 1 36: 1,2,3,4,6,9,12,...36. Therefore 36 is composite.

Crank4 years ago

4 0

36 because the rest are prime #'8

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Two competitive neighbours build rectangular pools that cover the same area but are different shapes. Pool A has a width of (x +

GenaCL600 [577]

Answer:

a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

b) Area of pool A is equal to area of pool B equal to 24.44 meters.

Solution:

Let’s first calculate area of pool A .

Given that width of the pool A = (x+3)

Length of the pool A is 3 meter longer than its width.

So length of pool A = (x+3) + 3 =(x + 6)

Area of rectangle = length x width

So area of pool A =(x+6) (x+3) ------(1)

Let’s calculate area of pool B

Given that length of pool B is double of width of pool A.

So length of pool B = 2(x+3) =(2x + 6) m

Width of pool B is 4 meter shorter than its length,

So width of pool B = (2x +6 ) – 4 = 2x + 2

Area of rectangle = length x width

So area of pool B =(2x+6)(2x+2) ------(2)

Since area of pool A is equal to area of pool B, so from equation (1) and (2)

(x+6) (x+3) =(2x+6) (2x+2)

On solving above equation for x

(x+6) (x+3) =2(x+3) (2x+2)

x+6 = 4x + 4

x-4x = 4 – 6

x = $\frac{2}{3}$

Dimension of pool A

Length = x+6 = ( $\frac{2}{3}$ ) +6 = 6.667m

Width = x +3 = ( $\frac{2}{3}$ ) +3 = 3.667m

Dimension of pool B

Length = 2x +6 = 2( $\frac{2}{3}$ ) + 6 = $\frac{22}{3}$ = 7.333m

Width = 2x + 2 = 2( $\frac{2}{3}$ ) + 2 = $\frac{10}{3}$ = 3.333m

Verifying the area:

Area of pool A = ( $\frac{20}{3}$ ) x ( $\frac{11}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Area of pool B = ( $\frac{22}{3}$ ) x ( $\frac{10}{3}$ ) = $\frac{220}{9}$ = 24.44 meter

Summarizing the results:

(a)Dimensions of pool A are length = 6.667m and width = 3.667 m and dimension of pool B are length = 7.333m and width = 3.333m.

(b)Area of pool A is equal to Area of pool B equal to 24.44 meters.

5 0

4 years ago

Please Answer these 3 question

Vadim26 [7]

Answer:

Alvin is a proportion relation with a rise/run of 10/1. Contrary Isabelle pays 3 dollars to rent shoes hence the 1st game cost 13 dollars and then the second game 6.

(2,20) means they are on the second game and the cost is 20 dollars

y= 10x

5 0

3 years ago

Select the two values of x that are roots of this equation. x2 - 5x + 2 = 0

Margaret [11]

Answer:

C and D

${x}^{2} - 5x + 2 = 0 \\ x = \frac{5± \sqrt{17} }{2}$