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makkiz [27]
3 years ago
6

Find the measure of angle y. Round your answer to the nearest hundredth. Right triangle

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0
<h3>The measure of angle y is 35.68 degrees</h3>

<em><u>Solution:</u></em>

Given that,

hypotenuse 12

Opposite 7

Find the measure of angle y

y is unknown and is between the hypotenuse and adjacent side

The figure is attached below

In a right triangle, the sine of the angle is the ratio of the side opposite to the angle to the hypotenuse

Therefore,

sin\ y = \frac{opposite}{hypotenuse}\\\\sin\ y = \frac{7}{12}\\\\sin\ y = 0.5833\\\\y = sin^{-1}\ 0.5833\\\\Use\ arcsin\ calculator\\\\y = 35.6829 \\\\y \approx 35.68

Thus measure of angle y is 35.68 degrees

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Jason’s savings account has a balance of $2179. After 5 years , what will the amount of interest be at 6% compounded quarterly?
satela [25.4K]

Answer:

$755.80

Step-by-step explanation:

Determine the compound amount first and then subtract the principal from it, to find the amount of interest.

The compound amount formula is A = P (1 + r/n)^(nt), where

P is the initial principal, r is the interest rate as a decimal fraction, n is the number of compounding periods per year, and t is the number of years.  Here, P = $2179; t = 5 yrs; r = 0.06; and n = 4 (quarterly compounding).

We get:

A = $2179(1 + 0.06/4)^(4*5), or $2179(1.015)^20, or $2179(1.347) = $2937.80.

The compound amount is $2934.80.  Subtracting the $2179 principal results in the interest earned:  $755.80.

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3 years ago
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2 years ago
Mandy has a total of $2.00 in change in her purse. Complete each set of coins below to show amounts equivalent to $2.00.
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Step-by-step explanation:

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2 years ago
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Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!
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\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span>\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.
\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.
--------------------
5y = 12
\boxed{\boxed{y =  \frac{12}{5}}}\end{array}}\qquad\quad\checkmark

Let's replace the value found in the first equation:
4x-3y=16\:(I)
4x-3*( \frac{12}{5}) =16
4x -  \frac{36}{5} = 16
least common multiple (5)
\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}
20x - 36 = 80
20x = 80 + 36
20x = 116
x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark



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3 years ago
Help 9th grade algebra
Naya [18.7K]

Answer:

Step-by-step explanation:

1. true

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3 years ago
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