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ikadub [295]
2 years ago
13

If x is an odd number, which of the following is also odd? * X + 1, X + 2, 2x + 2 or 3x + 1​

Mathematics
1 answer:
emmainna [20.7K]2 years ago
5 0

Answer:

x+2

Step-by-step explanation:

i put mi x as one so

....that how i get my anwser

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A figure in the first quadrant is rotated 180° counterclockwise about the origin. In which quadrant will the rotated figure appe
amm1812
I believe quadrant 3
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3 years ago
Read 2 more answers
I need help on solving this math problem.​
son4ous [18]

Answer:

f(1)=-3

f(-4)=-11

f(6)=0

Step-by-step explanation:

Use the correct formula depending on what (x) equals.

When (x=1) you use the second formula because 1 is greater than -2 but less than 4

When (x=-4) you use the first formula because -4 is less than -2

When (x=6) you use the third formula because 6 is greater than 4

5 0
3 years ago
An exam has two probability problems, 1 and 2. If 37% of the students solved problem 1 and 12% of the students solved both probl
yan [13]

Answer:

63%

Step-by-step explanation:

37% did not solve problem 2

100% - 37% = 63%

3 0
3 years ago
Kai marked up the new Kobe Grinch by 35% .She sole them for $168.75 . What was the original price
MrRissso [65]

Answer: 109.69

Step-by-step explanation:

100-35=65

168.75 • 65= 10,968.75/ 100= 109.69

8 0
3 years ago
The vertex of ∠A B C is located at the origin. Point A is located at (5,0) and Point C is located at (0,2). How can ∠A B C be cl
mixer [17]

As the angle is greater than 0° and less than 90°, then the angle ABC is acute. (Answer: A)

<h3>How to determine the features of an angle set on Cartesian plane</h3>

Herein we find the locations of the three vertices of the figure, of which we must determine the lengths of the two sides of the angle and determine the value of the angle by trigonometry:

BA = 5, BC = 2

θ = tan⁻¹ (BA / BC)

θ = tan⁻¹ (5 / 2)

θ ≈ 68.199°

As the angle is greater than 0° and less than 90°, then the angle ABC is acute. (Answer: A)

To learn more on acute angles: brainly.com/question/2761036

#SPJ1

8 0
1 year ago
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