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3 years ago

The equation 3x + 2 = 29 is modeled below.

Mathematics

2 answers:

DanielleElmas [232]3 years ago

7 0

Answer:

Subtract 2 from both sides.

Step-by-step explanation:

Remember to do the opposite of PEMDAS. PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

> Also, note the equal sign, what you do to one side, you do to the other side of the equation.

First step is to subtract 2 from both sides of the equation:

3x + 2 (-2) = 29 (-2)

3x = 29 - 2

3x = 27

The second step is to divide 3 from both sides of the equation:

(3x)/3 = (27)/3

x = 27/3

x = 9

klasskru [66]3 years ago

6 0

Answer:

The first step is subtracting the two on both sides.

Step-by-step explanation:

You arent exactly following PEMDAS in this equation, but you are still in a way. Before going on to x you need to go on to the numbers first. 3x would be equal to 27.

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castortr0y [4]

Answer: second option y = 2(x + 7/2)^2 + 1/2

Explanation:

1) given:

y = (x + 3)^2 + (x + 4)^2

2) expand the binomials:

y = x^2 + 6x + 9 + x^2 + 8x + 16

3) add like terms:

y = 2x^2 + 14x + 25

4) take common factor 2 of the first two terms:

y = 2 (x^2 + 7x) + 25

5) complete squares for x^2 + 7x

x^2 + 7x = [x +(7/2)x ]^2 - 49/4

6) substitue x^2 + 7x = (x + 7/2)^2 - 49/4 in the equation for y:

y = 2 [ (x + 7/2)^2 - 49/4] + 25

7) take -49/4 out of the square brackets.

y = 2 (x + 7/2)^2 - 49/2 + 25

8) add like terms:

y = 2(x + 7/2)^2 + 1/2

And that is the vertex for of the given expression.

7 0

3 years ago

Gianna skied three times farther than Xavier. Xavier skied four miles. How far did Gianna ski?

lana [24]

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3 years ago

Read 2 more answers

Proving the Parallelogram Diagonal Theorem

lora16 [44]

Answer:

The proof is given below.

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC (∵Opposite sides of parallelogram are equal)

∠DAC=∠BCE (∵Alternate angles)

∠ADC=∠CBE (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE