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sdas [7]
3 years ago
13

2,4,7,11,... what term is next and is it arithmetic or geometric

Mathematics
2 answers:
dedylja [7]3 years ago
7 0

Answer:

16

Step-by-step explanation:

count number to number which increase

2+2

4+3

7+4

11+5

ddd [48]3 years ago
6 0
This is geometric. The next term is 16. Ax+b. A is the initial value, b is the constant and x would be ur values to plug in to get those numbers
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The fraction wall of the concrete is 8/17.
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Which graph represent y = ^3 sqrt x-5
Juliette [100K]

The graph that represents 2+3 is the one that mean go add then multiply it to the equation that the number will be

3 0
3 years ago
Find dy/dx if y =x^3+5x+2/x²-1
stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

\qquad\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\

According to the given question, we have –

  • f(x) = x^3+5x+2
  • g(x) = x^2-1

Let's solve it!

\qquad\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2)  \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5)  -  ( x^3+5x+2) 2x}{(x^2-1)^2 }\\

\qquad\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\

\qquad\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\

\qquad\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\

\qquad\pink{\therefore  \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}}  =  \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\

7 0
2 years ago
Find the volume length 10 2/5 cm, width 3 cm, height 8 1/3 cm
AURORKA [14]

Answer:

260 cm

Step-by-step explanation:

formula for finding volume:

<u>l x w x h = v</u>

l=length   w=width    h=height    v=volume

10\frac{2}{5} × 3 × 8\frac{1}{3}

10\frac{2}{5} = \frac{52}{5}

how did i do that?

cross multiply the whole number and the denominator together and add the product by the numerator.

8\frac{1}{3} = \frac{25}{3}

so, \frac{52}{5} × \frac{25}{3} × \frac{3}{1}

cross simplify(dont have to do it just makes everything easier)

and you get:

\frac{52}{1} × \frac{5}{1} × \frac{1}{1}

and you get \frac{260}{1}

\frac{260}{1} = 260 cm

plz give me a brainliesttttt

4 0
3 years ago
Read 2 more answers
Find the area of a square with a diagonal of 8 cm.
Fofino [41]

Answer:

To find the area of a square with only the diagonal known,

Square the diagonal and divide by 2:

8^2 = 64

64/2 = 32

The area is 32 cm^2

3 0
3 years ago
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