100 points

CRITICAL THINKING A local zoo employs 36 people to take care of the animals each day. At most, 24 of the employees work full tim

k0ka [10]

We assume all employees are either full-time or part-time.

36 = 24 + 12

If the number of full-time employees is 24 or less, the number of part-time employees must be 12 or more. (Thinking, based on knowledge of sums.)

_____

You can write the inequality in two stages.

First, write and solve an equation for the number of full-time employees in terms of the number of part-time employees.
Then apply the given constraint on full-time employees. This gives an inequality you can solve for the number of part-time employees.

Let f and p represent the numbers of full-time and part-time employees, respectively.

... f + p = 36 . . . . . . given

... f = 36 - p . . . . . . . subtract p. This is our expression for f in terms of p.

... f ≤ 24 . . . . . . . . . given

... (36 -p) ≤ 24 . . . . substitute for f. Here's your inequality in p.

... 36 - 24 ≤ p . . . . add p-24

... p ≥ 12 . . . . . . . . the solution to the inequality

5 0

4 years ago

Round 13.3 to nearest tenths

LiRa [457]

It won't change........

It will be 13.3 after the rounding off, as in the question...

7 0

4 years ago

Read 2 more answers

A newspaper poll asked respondents if they trusted "eco friendly" labels on cleaning products. Out of 1000 adults surveyed, 498

Paul [167]

Answer:

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=498 represent the adults that trust these labels

$\hat p=\frac{498}{1000}=0.498$ estimated proportion of respondents that trust these labels

$p_o=0.5$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion of respondents that trust these labels is at least 50%:

Null hypothesis: $p\geq 0.5$

Alternative hypothesis: $p < 0.5$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.498 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=-0.126$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but we can assume it as $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.

7 0

4 years ago

Please help me?

lys-0071 [83]

<span>B. -6y = 12 is the asnwer</span>

4 0

3 years ago

Read 2 more answers

Jean is 11 years old. She lives in a building with 8 children who are older than 11 and 6 children that are under 11 years old H

Vladimir79 [104]

Answer:

Step-by-step explanation:8

3 0

4 years ago