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aleksandrvk [35]

3 years ago

9

The table shows partial results of a survey about students who speak foreign languages.

2 answers:

Lady bird [3.3K]3 years ago

8 0

THE ANSWER IS C (◡ ‿ ◡ ✿)

Elan Coil [88]3 years ago

7 0

Oh this is easy.I completed the table. C) 40%

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Megan and her sister are planning their

Yuri [45]

Answer: y = 12.50x + 45

Step-by-step explanation:

if x is the number of hours and you pay $12.50 per hour then we can come up the expression 12.50x

You will be charge $45 as an initial fee so it will be 12.50x + 45 and that has to equal the total cost which is y.

y = 12.50x + 45

7 0

3 years ago

3x7x7x7x7 in index notation <br>2x9x9x9x2x9<br>plz help<br>thx

Leto [7]

$3 \times {7}^{4}$
Because there's one 3 & four 7's .

${2}^{2} \times {9}^{4}$
Because there are two 2's & four 9's

4 0

3 years ago

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Describe and correct the error in writing the value of the product. 2 x 2 x 2 x 2 = 4²

OverLord2011 [107]

Answer:

2⁴

Step-by-step explanation:

4² would be 4x4 not 2x2x2x2

2x2x2x2 would be 2⁴.

6 0

3 years ago

The graph shows two lines, A and B.

Papessa [141]

Part A: One solution because the lines intersect one time.
Part B: (3,4) or x=3 and y=4 (depending on how you have to write it)

8 0

3 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

or

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

or

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

8 0

4 years ago

Read 2 more answers