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3 years ago

Where is the point (-2 -3) located in the coordinate plane

Mathematics

2 answers:

labwork [276]3 years ago

5 0

Answer:

It's located in the third quadrant

(X,Y)

Step-by-step explanation:

Margarita [4]3 years ago

5 0

Located in the third quadrant. It would be the bottom right one if you didn’t know.

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The recycling center pays $0.01 for each aluminum can recycled. Dan was payed $10.00 for all his aluminum cans. How many aluminu

Setler [38]

Answer:

1000

Step-by-step explanation:

To solve this you divide 10/0.01 and you get 1000.

Hope it helps!

8 0

3 years ago

2^x+5 = 3^1-x use logarithms to solve the exponential equation. round answer to 3 decimal places.

marysya [2.9K]

$2^{x+5}=3^{1-x}\ \ \ \ \ /log_2()\\\\log_22^{x+5}=log_23^{1-x}\\\\x+5=(1-x)log_23\\\\x+5=log_23-xlog_23\\\\x+xlog_23=log_23-5\\\\x(1+log_23)=log_23-5\ \ \ \ /:(1+log_23)$

$x=\frac{log_23-5}{1+log_23}\\-------------\\log_23\approx1.5849625\\----------------\\x\approx\frac{1.5849625-5}{1+1.5849625}\approx-1.321$

8 0

3 years ago

Read 2 more answers

An item is regularly priced at $70. Keiko bought it on sale for 80% off the regular price. How much did Keiko pay? $

pantera1 [17]

Answer:

$14

Step-by-step explanation:

80% of $70 is $14, saving him $56

8 0

2 years ago

Read 2 more answers

What is 329,625 rounded to the place value of the underlined digit?

dexar [7]

Answer:

330,000

Step-by-step explanation:

if the underlined digit is 9, then the six rounds the 9 up to a 10, making the rounded number amount to 330,000.

4 0

3 years ago

Read 2 more answers

If c is the curve given by \mathbf{r} \left( t \right = \left( 1 5 \sin t \right \mathbf{i} \left( 1 3 \sin^{2} t \right \mathbf

jonny [76]

With the curve $C$ parameterized by

$C:\mathbf r(t)=\underbrace{15\sin t}_{x(t)}\,\mathbf i+\underbrace{13\sin^2t}_{y(t)}\,\mathbf j+\underbrace{12\sin^3t}_{z(t)}\,\mathbf k$

with $0\le t\le\dfrac\pi2$ , and given the vector field

$\mathbf f(x,y,z)=x\,\mathbf i+y\,\mathbf j+z\,\mathbf k$

the work done by $\mathbf f$ on a particle moving on along $C$ is given by the line integral

$\displaystyle\int_C\mathbf f\cdot\mathrm d\mathbf r=\int\limits_{t=0}^{t=\pi/2}\mathbf f(x(t),y(t),z(t))\cdot\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\,\mathrm dt$

where

$\mathrm d\mathbf r=(15\cos t\,\mathbf i+26\sin t\cos t\,\mathbf j+36\sin^2t\cos t\,\mathbf k)\,\mathrm dt$

The integral is then

$\displaystyle\int_0^{\pi/2}(15\sin t\,\mathbf i+13\sin^2t\,\mathbf j+12\sin^3t\,\mathbf k)\cdot(15\cos t\,\mathbf i+13\sin2t\,\mathbf j+18\sin t\sin2t\,\mathbf k)\,\mathrm dt$
$=\displaystyle\int_0^{\pi/2}(432\sin^5t\cos t+338\sin^3t\cos t+225\sin t\cos t$
$=269$

6 0

3 years ago