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Allushta [10]
3 years ago
9

A construction crew is lengthening a road. The road started with a length of 56 miles, and the crew is adding 4 miles to the roa

d each day. Let L represent the total length of the road (in miles), and let D represent the number of days the crew has worked. Write an equation relating L to D . Then use this equation to find the total length of the road after the crew has worked 36 days.
Equation: ____

Total length of the road after 36 days: ___miles
Mathematics
1 answer:
Natalka [10]3 years ago
6 0
Your Equation=    L=56+4(D)
L=56+4(36)
L=56+144
L=200
After working for 36 days, the total length of the road is 200 miles
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1 1/25 is the fraction
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Write as a product:<br><br> a^3-m^3 n^9
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=−m3n9+a3

Step-by-step explanation:

Let's simplify step-by-step.

a3−m3n9

=a3+−m3n9

4 0
2 years ago
ANSWER ASAP!!!
denis23 [38]

Answer:

Then, the object will take 29.11 min to travel 4\frac{9}{10}miles

Step-by-step explanation:

When an object is moving at a steady speed, we can calculate the time it would take to travel a given distance using the following formula:

time=\frac{distance}{speed} (equation 1)

In this particular, both the given speed and distance are mixed fractions so we'll first convert them into improper fractions to operate more easily:

speed=10\frac{1}{10} \frac{mi}{h} =\frac{(10*10)+1}{10} \frac{mi}{h}=\frac{101}{10}  \frac{mi}{h}

distance=4\frac{9}{10}mi=\frac{(4*10)+9}{10}mi=\frac{49}{10}mi

So, now we can calculate the time using the equation 1:

time=\frac{distance}{speed}=\frac{\frac{49}{10}mi }{\frac{101}{10} \frac{mi}{h} } =\frac{49*10}{101*10} h

time=\frac{49}{101}h=0.49h

And, if we want the result in minutes:

time=\frac{49}{101}h*\frac{60min}{1h}  =29.11min

Then, the object will take 29.11 min to travel 4\frac{9}{10}miles

5 0
2 years ago
Please help me. I couldn't find the answer. I need prove how I got the answer as well ​
Naya [18.7K]

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13 car lengths

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Evaluating expressions:<br> 1. x + 9 when x = 3
balu736 [363]

⇨ The numeric value of this expression = 12.

<h3> </h3>
  • To solve this expression, just <u>replace '</u><u>x</u><u>'</u> by the <em>indicated value</em>, being the number 3, and <em>perform</em> the <em>indicated </em>math <em>operations</em>.

{\large \displaystyle \sf {1 \cdot x+9  }}

{\large \displaystyle \sf {x=3  }}

{\large \displaystyle \sf {1 \cdot 3+9  }}

{\large \displaystyle \sf { 3+9  }}

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

  • Therefore, we can conclude that, the correct value of this expression = 12.

{\orange{\boxed{\boxed{\pink {\large \displaystyle \sf { \ 12 \   }}}}}}\\\\

<h3><em>Hope this helps! ❤️</em></h3>

4 0
3 years ago
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