Question

Please Help!!!!

Answer 1

Step-by-step explanation:

Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC

To prove = ∠3= 49°

Solution:

In figure, m∥n cut by traversal t.

So,  ∠DEF = ∠ABC(alternative exterior angles)

∠1 + ∠2 = ∠4 + ∠5

∠ABC = ∠1 + ∠2 = 50° + 48° = 98°

Also given that s bisect angles ∠ABC.

∠4 = ∠5

∠ABC = ∠4 + ∠5 = 98°

∠4 + ∠4 = 98°

2∠4 = 98°

∠4 = 49°

∠4= ∠3 = 49° (vertically opposite angles)

∠3 = 49° ,hence proved