A11 1 * [ (2*5) - (5*2)] = 0
a12 = -4 *(5*5) - 2*1) = 23*-4 = -92
a13 = 4 * (5*5) - (1*2) = 23 * 4 = 92
a21 = 0
a22 = 2 * (5-4) = 2
a23 = -2 * (5-4) - -2
a31 = 0
a32 = -5*(2-20) = 90
a33 = 5 * (2-10) = -90
Adding these gives zero
Answer is B:- 0
So 3. put it on x. but the negative numbers . then 4 put. 5 on y
4x+3y=19 and 6x-5y=-57
eliminate
multiply first equation by -6 and 2nd by 4
and add them
-24x-18y=-114
<u>24x-20y=-228 +</u>
0x-38y=-342
-38y=-342
divide both sides by -38
y=9
sub back
4x+3y=19
4x+3(9)=19
4x+27=19
minus 27 both sides
4x=-8
divide 4
x=-2
(x,y)
(-2,9)
Answer:
x ≈ 1.28
Step-by-step explanation:
I just took the exam:
Area of rectangle =(3x-1)(x+6), Area of circle = PI(x+1)^2. If you graph these and find where they intersect, you will get x ≈ 1.28.
I hope this helped! :)