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mixas84 [53]
4 years ago
13

Jen's favorite band is going on tour this summer. There are eight different concert dates that Jen could attend. She can only af

ford to see three shows. How many possible combinations are available for Jen?
Mathematics
1 answer:
FrozenT [24]4 years ago
7 0
The number of <span>possible combinations can be calculated by formula C_n^k= \frac{n!}{k!(n-k)!}.
</span>
<span>There are eight different concert dates that Jen could attend, then n=8.
</span>
Jen <span>can only afford to see three shows, then k=3
</span>
and<span>
</span>

<span /><span /><span>C_8^3= \frac{8!}{3!(8-3)!}=\frac{1\cdot 2\cdot 3\cdot 4\cdot5 \cdot 6\cdot 7\cdot 8}{1\cdot 2\cdot 3\cdot 1 \cdot 2 \cdot 3 \cdot 4 \cdot 5} =56</span><span />

<span>Answer: 56 possible combinations.</span>







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The number of boxes renita and Vanessa has unpacked each is 6 and 9 boxes respectively.

<h3>Equation</h3>

  • Number of boxes renita has unpacked = x
  • Number of boxes Vanessa has unpacked = 2x - 3
  • Total boxes both unpacked = 15

x + (2x - 3) = 15

x + 2x - 3 = 15

3x = 15 + 3

3x = 18

x = 18/3

x = 6

Therefore,

Number of boxes renita has unpacked = x

= 6 boxes

Number of boxes Vanessa has unpacked = 2x - 3

= 2(6) - 3

= 12 - 3

= 9 boxes

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Each adult ticket has a different price value .
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Answer:

Step-by-step explanation:

c+a=20

a=20-c

5.25c+7.75a=140, using a from above makes this

5.25c+7.75(20-c)=140

5.25c+155-7.75c=140

-2.5c+155=140

-2.5c=-15

c=6

a=20-c=20-6=14

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The total cost of the bracelet will be $96.

The number of charms will be 2.

Step-by-step explanation:

Given,

Cost per charm at Dayton Fine Jewelry = $17

Cost of bracelet = $62

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x be the number of charms

y be the total cost

y = 17x+62   Eqn 1

Cost per charm at Cain Jewelers = $18

Cost of bracelet = $60

y = 18x+60   Eqn 2

For same cost;

Eqn 1 = Eqn 2

17x+62=18x+60\\62-60=18x-17x\\2=x\\x=2

Putting x=2 in Eqn 1

y=17(2)+62\\y=34+62\\y=96

Putting x=2 in Eqn 2

y=18(2) +60\\y=36+60\\y=96

The total cost of the bracelet will be $96.

The number of charms will be 2.

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