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4 years ago

Given triangle SZU, UJ=9,VJ=3 , what’s the length of JY?

Mathematics

2 answers:

Zielflug [23.3K]4 years ago

6 0

The answer to this is A.4.5 I took it

loris [4]4 years ago

4 0

$answer = 4.5 \\ solution \\ uj = 9 \\ vj = 3 \\ \frac{uj}{jy} = \frac{2}{1} \\ or \: \frac{9}{jy} = \frac{2}{1} \\ or \: 2 \times jy = 9 \times 1 \\ or \: 2 \: jy = 9 \\ or \: jy = \frac{9}{2} \\ jy = 4.5 \\ hope \: it \: helps$

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Answer:

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Step-by-step explanation:

Using the normal distribution we can find z value with the mean and standard deviation as follows. x is the value we want to know its probability

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The surface of a table to be built will be in the shape shown below. The distance from the center of the shape to the center of

velikii [3]

A) Add three line segments (AD, CF, BE) to the regular hexagon.

B) The area of each triangle of the regular hexagon is 35.1 in².

C) The area of the regular hexagon is 210.6 in².

<h3>How to calculate the area of a regular hexagon</h3>

In geometry, regular hexagons are formed by six regular triangles with a common vertex. We decompose the hexagon in six equilateral triangles by adding three line segments (AD, CF, BE).The area of each triangle is found by the following equation:

A = 0.5 · (9 in) · (7.8 in)

A = 35.1 in²

And the area of the regular polygon is six times the former result, that is, 210.6 square inches.

To learn more on polygons: brainly.com/question/17756657

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3 years ago

a rectangular pool is 20 ft wide and 50 ft long. the deck is the same width all the way around the pool. the total area of the d

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First, we need to get the total area of the rectangular pool.
Area = l * w
Area = 20 ft * 50 ft
Area = 1000 ft^2

Then the deck is 456 ft^2 with the width of 20ft, the same as the rectangular pool.

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456 = l * 20
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3 years ago