For this right triangle shown, what is the sine of angle C?

Mathematics

1 answer:

choli [55]3 years ago

5 0

Answer:

8.212°

Step-by-step explanation:

Hypotenuse^2=base^2+perp^2

(8)^2=(7)^2+(perp)^2

64=49+(perp)^2

64/49=perp^2

1.306=perp^2

Now taking sq root on both sides

Perp=√1.306

Perp=1.142

Sin C=opposite/hypotenuse

Sin C=1.142/8

Sin C=0.14285

C=Sin^-1 0.14285

C=8.212°

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Answer:

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