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Iteru [2.4K]
3 years ago
15

Solve the inequality using the algebraic approach: x+2>3x-8

Mathematics
1 answer:
kow [346]3 years ago
4 0
X + 2 > 3x - 8
subtract x from both sides

2 > 2x - 8
add 8 to both sides

10 > 2x
divide both sides by 2

5 > x


ANSWER: 5 > x

Hope this helps! :)
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Keith_Richards [23]

Answer:

−(3x−2)(7x+4)

Step-by-step explanation:

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On a number line 6.64 would be located 
Dominik [7]

Answer:

yes

Step-by-step explanation:

7 0
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If u = 2i - j; v= -5i + 4j and w = j find 4u (v -w).
Sedaia [141]

Answer:

-40

Explanation:

Given

u = 2i - j; v= -5i + 4j and w = j

Required

4u(v-w)

4u = 4(2i) = 8i

v - w = -5i + 4j - j

v - w = -5i + 3j

Substitute

4u(v-w)

= 8i(-5i+3j)

= -40(i*i) [since i*i = 1]

= -40

Hence the required solution is -40

5 0
1 year ago
Which equation describes the line that passes through the points (-4, 19) and (2, -1)
dangina [55]

Answer:

y=-5/2x+4

Step-by-step explanation:

find the slope by using y2-y1/x2-x1

-1-19/2-(-4)

simplify

-20/8

simplify

-5/2

use slope-intercept form, y=mx+b

since we know the slope, find b

plug in one of the ordered pairs into the equation

-1=(-5/2)(2)+b

simplify

-1= -10/2+b

simplify

-1=-5+b

add 5 to both sides

b=4

plug b into y=-5/2x+b

y=-5/2x+4

8 0
2 years ago
Read 2 more answers
On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
3 years ago
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