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elena55 [62]
3 years ago
12

Fill in the bubble next to all the doubles facts you could use to fined the sum of 4+5

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0
4+4 hope this helps you out :)
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50 POINTS!!! PLEASE HELP QUICK! In the figure below, AB is a diameter of circle P.
Minchanka [31]

Answer:

43°

Step-by-step explanation:

7x+1+9x-7=90

16x-6=90

16x=96

x=6

the minor arc AD = 7x+1 =7(6)+1

= 42+1=43°

6 0
3 years ago
Help with this plzzzzzz
NISA [10]

Answer:

C. 11:16 AM

Step-by-step explanation:

Subtract 42 minutes from 58, which is 16. To find out what hour, you subtract by 3. When you do subtract, the answer is 11 AM.

Hope this helps :)

5 0
3 years ago
2×+10=74 find the value of x​
WARRIOR [948]

Answer:

x=32

Step-by-step explanation:

2x+10=74

2x=64

x=32

7 0
3 years ago
Read 2 more answers
Can someone help me with this
mash [69]

The center of the circle is (h,k) = (-2,-3)

The radius of the circle is r = 2

The standard form of equation of the circle is

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

<h3>How to find the center, radius and standrad form of the circle?</h3>

The general form of equation of the circle is

{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

Here, (h,k) means centre of the circle.

r means radius of the circle.

given that coordinate points of centre of circle is (-2,-3).

Hence the (h,k) = (-2,-3)

<h3>How to find the radius of the circle?</h3>

Now to find the radius of the circle

The distance from a circle's centre to its circumference is its radius.

The distance from a circle's centre (-2,-3) to its circumference (0,-3) is its radius.

using the formula, distance between the two points to obtain radius.

d =  \sqrt{(x1 - x2) {}^{2}  +  {(y1 - y2)}^{2} }  \\ r =  \sqrt{ {( - 2 - 0)}^{2} +  {( - 3 - ( - 3))}^{2}  }  \\ r =  \sqrt{ {( - 2)}^{2} +  {( - 3 + 3)}^{2}  }  \\ r =  \sqrt{ {4}^{2} + 0 }  \\ r =  \sqrt{4}  \\ r = 2

<h3>How to find the standard form of equation of the circle?</h3>

(h,k) = (-2,-3)

r = 2

subtitue the (h,k) and r values to get the standard form of equation of the circle.

(x - h) {}^{2}  +  {(y - k)}^{2}  =  {r}^{2}

{(x - ( - 2))}^{2}  +  {(y - ( - 3))}^{2} =  {r}^{2}

{(x + 2)}^{2}  +  {(y + 3)}^{2}  = 4

Learn more about circle, refer:

brainly.com/question/24810873

#SPJ9

5 0
1 year ago
What are the complex zeros of y = x4 +9​
Serjik [45]

Answer:

The answer is <em><u>x  =  4√ − 9 ,  − 4 √ − 9</u></em>!

The 4 is a part of the radical (-9^1/4)

4 0
3 years ago
Read 2 more answers
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