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4 years ago

6

What are the domain and range of the function below? !!!!!!

1 answer:

Diano4ka-milaya [45]4 years ago

8 0

Answer:

we need to see the whole graph to determine the domain and range please

Step-by-step explanation:

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What is the value of y?

attashe74 [19]

Answer:

-1

Step-by-step explanation:

5 0

3 years ago

Find the value of x <br>a. 31<br>b. 46<br>c. 52<br>d. 107

forsale [732]

The answer is C.52

4x-101=2x+3
2x =104
X=52

3 0

3 years ago

Find BC.( the value of x)<br> 1. 2.3 cm<br> 2. 2 cm<br> 3. 1.5 cm<br> 4. 1.2 cm<br> PLEASE HELP!!

elena-14-01-66 [18.8K]

It's a proportion.
2 is to x as 15 is to 9, or 2/x = 15/9.
Multiply the means and extremes
15x = 18
divide both sides by 15 to get x by itself.
x = 1.2

4 0

3 years ago

Read 2 more answers

Solve the problem.A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course. At that t

Mice21 [21]

Given:

A plane flying a straight course observes a mountain at a bearing of 35° to the right of its course.

The distance between plan and mountain is 10 km.

A short time later, the bearing to the mountain becomes 45°.

Here NM is the distance between the plane from the mountain when the second bearing is taken.

We need to find the measure of NM.

$We\text{ know that }\angle INM\text{ and }\angle\text{XNM are supplementary angles.}$

The sum of the supplementary angles is 180 degrees.

$\angle INM+\angle XNM=180^o$ $\text{Substitute }\angle XNM=45^o\text{ in the equation.}$

$\angle INM+45^o=180^o$

$\angle INM=180^o-45^o$

$\angle INM=135^o$

We know that the sum of all three angles of the triangle is 180 degrees.

$\angle INM+\angle NIM+\angle INM=180^o$ $\text{Substitute }\angle INM=135^o\text{ and }\angle NIM=35^o\text{ in the equation.}$

$135^o+35^o+\angle INM=180^o$

$170^o+\angle INM=180^o$

$\angle INM=180^o-170^o$

$\angle INM=10^o$

Consider the sine law.

$\frac{\sin N}{IM}=\frac{\sin M}{IN}=\frac{\sin I}{NM}$

Take the equation to find the measure of NM.

$\frac{\sin N}{IM}=\frac{\sin I}{NM}$ $\text{Substitute }\angle N=135^o,\angle I=35^o,\text{ and IM=10 in the equation.}$

$\frac{\sin 135^o}{10}=\frac{\sin35^o}{NM}$

$NM=\frac{\sin 35^o}{\sin 135^o}\times10$ $NM=8.11$

Hence the measure of NM is 8.1 km.

The plane is 8.1 km far from the mountain when the second bearing is taken.

5 0

1 year ago

Find the area of the triangle, i will give brainliest

GenaCL600 [577]

109
21.8x10=218
218 divided by 2 = 109

4 0

2 years ago