Answer:
Therefore the inverse function of
is 
Explanation:
We need to find the inverse of function 
Function Inverse definition :







Simplify














Therefore the inverse function of
is 
Answer:
1.
DIM myArray(10) as INTEGER
LET A = 0
FOR I = 1 TO 10 STEP 2
INPUT “INPUT NUMBER”; myArray(i)
LET A = A + myArray(i)
NEXT
PRINT A
END
2.
REM PROGRAM FOR CALCULATING THE SIMPLE INTEREST
CLS
INPUT “INPUT THE PRINCIPAL”; P
INPUT “INPUT THE TIME”; T
INPUT “INPUT THE RATE”;R
SI = P* T * R / 100
PRINT “SIMPLE INTEREST =”; SI
END
Explanation:
Please find the respective programs in the answer section.
Answer:
Boolean Operators
Explanation:
When performing a boolean search, boolean operators allow users to combine keywords with operators (or modifiers) such as AND, NOT and OR to further produce more relevant results.
The boolean operators AND and OR are used to include certain words and phrases during the search while the boolean operator NOT is used to exclude certain words and phrases.