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mart [117]
3 years ago
11

For the first 2 home football games, the concession stand sold a total of 70 hamburgers. How many hamburgers can they expect to

sell for all 11 games? Round to the nearest hamburger.
Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

385 hamburgers.

Step-by-step explanation:

So the data they have given us is that there have been 2 home games, with 70 hamburgers sold. If we divide the number of hamburgers sold by the number of games (70/2), we come up with the average hamburgers sold per game, which is 35. We can use an equation to find the amount of hamburgers sold for every x amount of games. h = 35x, with x being the amount of games, and h being the total amount of hamburgers. If you plug in 11 for x, you will get 385.

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Danielle’s chemistry professor has a complicated grading system. Each lab counts once and each test counts as two labs. At the e
Murrr4er [49]

Answer:

92

Step-by-step explanation:

Lab Scores are 84, 81, and 93

Test Scores are 89 and 94

Each lab counts once and each test counts as two labs. At the end of the semester there is a final lab that counts as three regular labs.

Total Number of Labs= (3X1)+(2X2)+(1X3) =3+4+3 =10

To recieve an A(90), the average of her scores must be 90.

Let her final lab score =b

Refer to the attached diagram

Total Score=624+3b

For her average =90

\frac{624+3b}{10}=90

Cross multiplying

624+3b =90 X 10

624+3b =900

3b =900-624

3b =276

Dividing both sides by 3

b= 92

She must score 92 in her final lab to receive an A.

6 0
3 years ago
Please help me gow to this bro , im confused
Airida [17]
Ok so remember that a circle is 360 degrees and a line is 180 degrees
so

IKJ
ok so we see that we have a triangle
to find the internal angles (which add to 180)
we do, opposite angles are equal
JIK=59
also CJI+KJI=180 so 132+KJI=180, KJI=48
so
59+48+IKJ=180
73=IKJ




HIB
we can assume that AB is paralell to CD
so therefor IJK=HIB=48 (from previous question)

EIJ is adding to EIH to get 180
EIJ+59=180
EIJ=121

AIK=AIJ+JIK
JIK=59
AIJ=HIB=48
AIK=59+48=107


IKJ=73
HIB=48
EIJ=121
AIK=107
6 0
2 years ago
Witch equation has the correct sign on the product.
maria [59]

Answer: choice A or (-25)(-25)=625

Step-by-step explanation:

its choice A because a negative times a negative equals a positive :)

4 0
2 years ago
Read 2 more answers
Find the volume of a regular hexahedron if one of the diagonals of its faces is 8 root 2 inches.
Naily [24]
The answer is 114sqrt{6} in³

A regular hexahedron is actually a cube. 

Diagonal of a cube D is a hypotenuse of a right triangle which other two legs are face diagonal (f) and length of a side (a):
D² = f² + a²

Face diagonal is a hypotenuse of a right triangle which sides are a and a:
f² = a² + a² =2a²

D² = f² + a²
f² = 2a²

D² = 2a² + a² = 3a²
D = √3a² = √3 * √a² = √3 * a = a√3

Volume of a cube with side a is: V = a³
D = a√3
⇒ a = D/√3

V = a³ = (D/√3)³

We have:
D = 8√2 in

V= (\frac{D}{ \sqrt{3} } )^{3} =( \frac{8 \sqrt{2} }{ \sqrt{3} } )^{3}=( \frac{8 \sqrt{2} * \sqrt{3} }{ \sqrt{3}* \sqrt{3}} )^{3} =( \frac{8 \sqrt{2*3} }{ \sqrt{3*3}} )^{3} =( \frac{8 \sqrt{6} }{ \sqrt{3^{2} }} )^{3} =( \frac{8 \sqrt{6} }{ 3} )^{3} = \\ \\ = \frac{ 8^{3} *( \sqrt{6} )^{3}}{3^{3}} = \frac{512* \sqrt{6 ^{2} }* \sqrt{6} }{27} = \frac{512*6* \sqrt{6} }{27} = 114sqrt{6}
8 0
3 years ago
To some Marines one cruising at 25 kn in the other 20 kn left the naval base at the same moment. Three hours later they were 100
Rus_ich [418]
I believe you would have to multiply both 25 and 20 and what ever number you get dived by 100 if the numbers to high multiply aging or subtract the number (if it's wrong I'm really not good at my math I'm sorry)
3 0
3 years ago
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