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mart [117]
3 years ago
11

For the first 2 home football games, the concession stand sold a total of 70 hamburgers. How many hamburgers can they expect to

sell for all 11 games? Round to the nearest hamburger.
Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

385 hamburgers.

Step-by-step explanation:

So the data they have given us is that there have been 2 home games, with 70 hamburgers sold. If we divide the number of hamburgers sold by the number of games (70/2), we come up with the average hamburgers sold per game, which is 35. We can use an equation to find the amount of hamburgers sold for every x amount of games. h = 35x, with x being the amount of games, and h being the total amount of hamburgers. If you plug in 11 for x, you will get 385.

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Step-by-step explanation:

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For each fraction, decimal, or percent, write the equivalent number from the list below. 0.68, 19/50, 9/20, 80%, 0.54. A. 38% __
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Step-by-step explanation:

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2 years ago
Chevy has some yarn that he wants to use to make hats and scarves. Each hat uses 0.20.20, point, 2 kilograms of yarn and each sc
Rashid [163]

Answer:

The system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Also 5 hats and 10 scarves can be prepared from 2 kg of yarn.

Step-by-step explanation:

Let number of hat Chevy makes be h.

Also Let number of scarves Chevy makes be s.

Given:

Total Amount of yarns = 2 kg

Total number of items = 15

Since Items need to make are hat and scarves.

Hence the equation can be represented as;

h+s=15 \ \ \ \ equation \ 1

Again Given:

Each hat uses 0.2 kilograms of yarn.

each scarf uses 0.1 kilograms of yarn.

Hence the equation can be represented as;

0.2h+0.1s=2 \ \ \ \ \ equation \ 2

Hence the system of equation that represent this situations are;

\left \{ {{h+s=15} \atop {0.2h+0.1s=2}} \right.

Now Solving these to find number of hats and number of scarves.

Multiplying equation 2 with 10 we get;

10(0.2h+0.1s)=2\times 10\\10\times0.2h+10\times0.1s=20\\2h+s =20 \ \ \ \ \ equation \ 3

Now Subtracting equation 1 from equation 3 we get;

(2h+s)- (h+s) =20-15\\2h+s-h-s=5\\h= 5

Now Substituting the value of h in equation 1 we get;

h+s= 15\\5+s =15\\s=15-5\\s=10

Hence 5 hats and 10 scarves can be prepared from 2 kg of yarn.

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