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3 years ago

Plz help theses are exponents

Mathematics

1 answer:

ohaa [14]3 years ago

3 0

For number 30 its 3
10

for 34 its 2
1/3

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A quadrilateral is a parallelogram only if both pairs of opposite sides are equal.

monitta

Answer:

True

Step-by-step explanation:

A parallelogram is a quadrilateral with 4 sides and both pairs of opposite sides are equal.

6 0

3 years ago

Read 2 more answers

Factor completely<br> B. (x+5)²-2(x+5)-24<br> C. (x+2)²-8(x+2)+15<br> D. 2(2x-1)²-9(2x-1)+4

Sladkaya [172]

B.
${x}^{2} + 10x + 25 - 2x - 10 - 24 = \\ x {}^{2} + 8x - 9 = \\ (x - 1)(x + 9)$

C.
${x}^{2} + 4x +4 - 8x - 16 + 15 = \\ x {}^{2} - 4x + 3 = \\ (x - 3)(x - 1)$
D.
$2( {4x}^{2} - 4x + 1) - 18x + 9 + 4 = \\ 8x {}^{2} - 8x + 2 - 18x + 13 = \\ 8x {}^{2} - 26x + 15$

please mark as brainliest.

3 0

3 years ago

Help pleaseeeeeeeeee

enot [183]

Put the answer choice numbers where the x’s are in the equation and then solve. The ones that are equal to 0 once solved will be your answer

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2 years ago

Read 2 more answers

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

Need help. How do I do this

lara [203]

9514 1404 393

Answer:

Step-by-step explanation:

Use the distance formula with the two points Q and P, then simplify and match the pattern of the answer.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(b-0)^2+(-c-(-a))^2}\\\\\boxed{d=\sqrt{b^2+(-c+a)^2}}$

The value b goes in the green box.

6 0

2 years ago