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zepelin [54]
3 years ago
10

True or false: Least squares regression problems always have a unique solution, since they are modelled by the normal equation

Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer: (((trueeee))))

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A production manager at a wall clock company wants to test their new wall clocks. The designer claims they have a mean life of 1
Harman [31]

The probability that the mean clock life would differ from the population mean by greater than 12.5 years is 98.30%.

Given mean of 14 years, variance of 25 and sample size is 50.

We have to calculate the probability that the mean clock life would differ from the population mean by greater than 1.5 years.

μ=14,

σ=\sqrt{25}=5

n=50

s orσ =5/\sqrt{50}=0.7071.

This is 1 subtracted by the  p value of z when X=12.5.

So,

z=X-μ/σ

=12.5-14/0.7071

=-2.12

P value=0.0170

1-0.0170=0.9830

=98.30%

Hence the probability that the mean clock life would differ from the population mean by greater than 1.5 years is 98.30%.

Learn more about probability at brainly.com/question/24756209

#SPJ4

There is a mistake in question and correct question is as under:

What is the probability that the mean clock life would differ from the population mean by greater than 12.5 years?

5 0
2 years ago
Cameron sponsor a fun raiser that 582 people attended he raise $6480 he charged $15 for balcony seats and $10 for crown seats ho
bagirrra123 [75]

Answer:

132 people bought balcony tickets and 450 bout ground tickets

Step-by-step explanation:

let x be balcony and y for ground

x+y=582

15x+10y=6480  solve by adding(subtracting)/eliminating process

multiply first equation by 15 to eliminate x:

15x+15y=8730

15x+10y=6480      subtract

15x+15y-15x-10y=8730-6480

5y=2250

y=2250/5=450

x+y=582

x=582-450=132

8 0
3 years ago
Add.
lidiya [134]
The answer is c:
87.872
5 0
4 years ago
After 9 new members joined the ski club, there were 38 members. How many members had been in the club previously?
stellarik [79]

Answer:

29 .

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
The durations (minutes) of 26 electric power outages in Shah Alam over the past five years are shown below. 32 44 25 66 27 12 62
Leto [7]

Answer:

Mean = 33.31

Median = 26

Mode = 17

Step-by-step explanation:

Given the data:

32 44 25 66 27 12 62 9 51 4 17 50 35 99 30 21 12 53 25 2 18 24 84 30 17 17

Reordered data : 2, 4, 9, 12, 12, 17, 17, 17, 18, 21, 24, 25, 25, 27, 30, 30, 32, 35, 44, 50, 51, 53, 62, 66, 84, 99

The mean, xbar = Σx / n = 866 /26 = 33.31

The median = 1/2(n+1)th term

Median = 1/2(27)th term = 13.5th term

Median = (13 + 14)th / 2

Median = (25 + 27) / 2 = 26

The mode = 17 (highest frequency)

4 0
3 years ago
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