Use expanded form or number name to complete the definition.

A home improvement store buys snow shovels from a supplier for $8.50. The day before a snowstorm the store manager marks up the

balandron [24]

Answer:

The retail price is $15.30

Step-by-step explanation:

To solve this, turn the percentage into a decimal. Do this by dividing it by 100.

180 ÷ 100 = 1.8

Then, multiply the supplier price by the decimal

8.5 × 1.8 = $15.30

7 0

3 years ago

Solve for w. -4 + w =-10

nignag [31]

w=-6 because you subtract -4 from -10 so the answer is -6

8 0

4 years ago

Read 2 more answers

HELP PLEASE PICTURE EXPLAINS EVERYTHING!!!!

allochka39001 [22]

Answer:

(a) Slope of Line 1 = 3

Slope of Line 2 = 3

Slope of Line 3 = -1/3

(b)

Line 1 and Line 2 = Parallel

Line 1 and Line 3 = Perpendicular

Line 2 and Line 3 = Perpendicular

Step-by-step explanation:

Please mark as brainliest! Thanks! Hope this helps!

4 0

3 years ago

If a > b > c > d, then which is larger, a+c or b+d ? Can we tell from a > b > c > d which of a+d and b+c is la

victus00 [196]

Answer:

1. a+c is larger than b+d

2. No way to tell whether a+d or b+c is larger.

Step-by-step explanation:

1. Which is larger, a+c or b+d?

Let a, b, c, and d be any numbers such that $a > b > c > d$ .

Specifically, note that $a > b$ , and subtracting b from both sides of the inequality, observe that $a-b > 0$ .

Similarly, $c > d$ , and subtracting d from both sides of the inequality, observe that $c-d > 0$ .

From this, add "a-b" (a positive number, as proven above) to both sides of the inequality.

$(a-b)+(c-d) > (a-b)+0$

Addition by zero (the additive identity) doesn't change anything, so the right side remains "a-b"...

$(a-b)+(c-d) > a-b$

... and "a-b" is positive...

$(a-b)+(c-d) > a-b > 0$

... so, by the transitive property of inequality...

$(a-b)+(c-d) > 0$

Recall that subtraction is addition by a negative number...
$a+(-b)+c+(-d) > 0$

...and that addition is associative and commutative, so things can be added in any order, so the middle two terms on the left side can be rearranged...

$a+c+(-b)+(-d) > 0$

Adding b + d to both sides of the inequality

$(a+c+(-b)+(-d))+(b+d) > 0+(b+d)$

... and simplifying

$a+c > b+d$

So, a+c is larger than b+d.

2. Which is larger, a+d or b+c?

Consider the following two examples:

Example 1

Suppose a=10; b=3; c=2; d=1.

Note that $a > b > c > d$ ( $10 > 3 > 2 > 1$ ) and, also observe that $a+d=(10)+(1)=11$ , and $b+c=(3)+(2)=5$ , so a+d is larger than b+c.

Example 2

However, suppose a=10; b=9; c=8; d=1.

Note that $a > b > c > d$ ( $10 > 9 > 8 > 1$ ) but that $a+d=(10)+(1)=11$ , and $b+c=(9)+(8)=17$ , so a+d is smaller than b+c.

So, in one example, a+d is bigger, and in the other, a+d is smaller. Therefore, there is no way to tell which of a+d or b+c is larger from only the given information.

5 0

2 years ago

The following drawing contains two _ angels.

Dvinal [7]

We need to see a picture

4 0

3 years ago