The Solution:
The correct answer is [option B]
Given:
Required:
To determine the inequality represented by the given number line.
The percent error is -2.1352% of Jocelyn's estimate. May I have Brainless
Answer:
3
Step-by-step explanation:
from the question, (-2,2) and (1,2) have the same y value so you can use that as your base and easily find the perpendicular height using the y axis since it's parallel to the x axis.
the third point, (0,-6), to the base is your height
use the sum of the positive of the y values to find your height (because height can't be negative): 6+2 = 8
area of a triangle = 1/2 bh = 1/2 x 3 x 8 = 12
Note: 1/2 bh only works because (-2,2) and (1,2) form a line parallel to the x axis
Answer:
![\left[\begin{array}{ccc}-25&\dfrac{75}{2}&-\dfrac{25}{2}\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%26%5Cdfrac%7B75%7D%7B2%7D%26-%5Cdfrac%7B25%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
In the first equality
![5\times \left[\begin{array}{cc}-1&2\\4&8\end{array}\right] =\dfrac{2}{5}m\times \left[\begin{array}{cc}-1&2\\4&8\end{array}\right],](https://tex.z-dn.net/?f=5%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5C4%268%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cdfrac%7B2%7D%7B5%7Dm%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5C4%268%5Cend%7Barray%7D%5Cright%5D%2C)
the matrices in both parts are the saem. The equality will be true if the same matrices are multiplied by the same numbers, so
![5=\dfrac{2}{5}m\Rightarrow m=5\times \dfrac{5}{2}=\dfrac{25}{2}](https://tex.z-dn.net/?f=5%3D%5Cdfrac%7B2%7D%7B5%7Dm%5CRightarrow%20m%3D5%5Ctimes%20%5Cdfrac%7B5%7D%7B2%7D%3D%5Cdfrac%7B25%7D%7B2%7D)
For the second equality
![(H+[1\ 4\ -2])+[3\ 2\ -6]=[-2\ 3\ -1]+([1\ 4\ -2]+[3\ 2\ -6]),](https://tex.z-dn.net/?f=%28H%2B%5B1%5C%204%5C%20-2%5D%29%2B%5B3%5C%202%5C%20-6%5D%3D%5B-2%5C%203%5C%20-1%5D%2B%28%5B1%5C%204%5C%20-2%5D%2B%5B3%5C%202%5C%20-6%5D%29%2C)
if
, then this equality represents the assotiative property of matrix addition.
Hence,
![m\times H=\dfrac{25}{2}\times [-2\ 3\ -1]=\left[\begin{array}{ccc}-25&\dfrac{75}{2}&-\dfrac{25}{2}\end{array}\right]](https://tex.z-dn.net/?f=m%5Ctimes%20H%3D%5Cdfrac%7B25%7D%7B2%7D%5Ctimes%20%5B-2%5C%203%5C%20-1%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%26%5Cdfrac%7B75%7D%7B2%7D%26-%5Cdfrac%7B25%7D%7B2%7D%5Cend%7Barray%7D%5Cright%5D)