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2 years ago

What is d/5>4? inequalities

Mathematics

1 answer:

Furkat [3]2 years ago

5 0

The problem to solve is:

d/5>4

First, let's work on the left hand side of your inequality, the d/5
This means, for instance, to see if it can be simplified at all.
 To divide d by 1 The d just gets copied along in the numerator. The answer is d d/5 evaluates to 1/5d So, all-in-all, the left hand side of your inequality can be written as:1/5d Now, let's work on the right hand side of your inequality, the 4
 The right hand side of your inequality can be written as: 4 So with these (any) simplifications, the inequality we'll set out to solve is:
1/5d > 4

To isolate the d, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)
around the d on the left side of the inequality.
The last step is to divide both sides of the inequality by 1/5 like this:
 To divide d by 1 The d just gets copied along in the numerator. The answer is d 1/5d ÷ 1/5 = d 4 ÷ 1/5 = 20

 The solution to your inequality is:

d > 20 
So, your solution is:
d must be greater than 20. 

HOPE THIS HELPS!

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Scorpion4ik [409]

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NISA [10]

Y = -4x - 2
P (-16, -11)
a = -4, b = 0, c = -2
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m = -(-4)/(-2)
m = 4/(-2)
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A outra questão é semelhante.

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3 years ago

In the Ardmore Hotel, 20 percent of the guests (the historical percentage) pay by American Express credit card. (a) What is the

xxMikexx [17]

Answer:

(a) The expected number of guests until the next one pays by American Express credit card is 4.

(b) The probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

Step-by-step explanation:

The random variable X can be defined as the number of guests until the next one pays by American Express credit card

The probability that a guest paying by American Express credit card is, p = 0.20.

The random variable X follows a Geometric distribution since it is defined as the number of trials before the first success.

The probability mass function of X is:

$P(X=x)=(1-p)^{x}p;\ x=0,1,2,3...,\ 0$

(a)

The expected value of a Geometric distribution is:

$E(X)=\frac{1-p}{p}$

Compute the expected number of guests until the next one pays by American Express credit card as follows:

$E(X)=\frac{1-p}{p}$

$=\frac{1-0.20}{0.20}$

$=4$

Thus, the expected number of guests until the next one pays by American Express credit card is 4.

(b)

Compute the probability that the first guest to use an American Express is within the first 10 to checkout as follows:

$P(X=10)=(1-0.20)^{10}\times0.20$

$=0.1073741824\times 0.20\\=0.02147483648\\\approx0.0215$

Thus, the probability that the first guest to use an American Express is within the first 10 to checkout is 0.0215.

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