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yan [13]
3 years ago
7

What formula is used to find the rate of change

Mathematics
1 answer:
Yuliya22 [10]3 years ago
7 0

Answer:

Average rate of change uses the slope formula (AKA rise over run AKA change in y over change in x AKA y2-y1 over x2-x1). To find y2 and y1, plug the x-values from your interval end points into the function f(x). Say f(1) and f(a). i really hope that helps

Step-by-step explanation:

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11. Reason Identify each solution as rational or
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Answer:

a. Rational; b. rational

Step-by-step explanation:

A rational number is the quotient of two integers.

a. ⁴/₇ + ⁻¹/₃

\begin{array}{rcl}\dfrac{4}{7} + \dfrac{-1}{3} & = & \dfrac{12}{21} + \dfrac{-7}{21} \\\\& = & \dfrac{5}{21}\\\end{array}

The solution is rational.

b. √4 ⅖

\begin{array}{rcl}\sqrt{4} \, \dfrac{2}{5} & = & 2 \, \dfrac{2}{5}\\\\& = & \dfrac{22}{5}\\\end{array}

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3 years ago
Si el lado de un cuadrado mide 10cm cuanto mide él área del círculo que se encuentra adentro de ese cuadrado
Alex17521 [72]

Answer:

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

Step-by-step explanation:

Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.

Ahora nos fijamos que necesitamos saber para calcular el área de un circulo

a = área

r = radio

π = 3.14

a = π * r²

como podemos ver no sabemos el valor del radio

como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.

Entonces tenemos que dividir un lado por 2

10cm/2 = 5cm

El radio del circulo sera 5cm

Ahora que tenemos todos los datos podemos calcular el valor del área

a = 3.14 * (5cm)²

a = 3.14 * 25cm²

a = 78.5cm²

El área del círculo que se encuentra en el cuadrado es de 78.5cm²

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3 years ago
A jar can fit up to 125 gumballs write an inequality to represent the number the jar can hold
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#gumballs is < or = to 125
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What is 7=b/11 what is b
alina1380 [7]
7 = b/11

11 × 7 = 77

Answer:

b = 7
7 0
2 years ago
Read 2 more answers
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